X = number of flower choices
We have 4 times of trees and 6 kinds of shrubs and x kinds of flowers
Overall, we'll have 4*6*x = 24*x different ways to pick three items (one per type).
Set this expression equal to 168 and solve for x
24*x = 168
24*x/24 = 168/24
x = 7
Answer: B) 7
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
![(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120](https://tex.z-dn.net/?f=%28%5E%7B10%7D%20_3%29%3D%5Cfrac%7B10%21%7D%7B3%21%2810-3%29%21%7D%3D%5Cfrac%7B10%21%7D%7B3%21%20%5Ctimes%207%21%7D%3D%5Cfrac%7B7%21%20%5Ctimes%208%20%5Ctimes%209%20%5Ctimes%2010%7D%7B6%20%5Ctimes%207%21%7D%3D%5Cfrac%7B8%20%5Ctimes%209%20%5Ctimes%2010%7D%7B6%7D%3D%5Cfrac%7B720%7D%7B6%7D%3D120)
You can choose 3 people in 120 ways.
You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
![(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15](https://tex.z-dn.net/?f=%28%5E6%20_2%29%3D%5Cfrac%7B6%21%7D%7B2%21%20%286-2%29%21%7D%3D%5Cfrac%7B6%21%7D%7B2%21%20%5Ctimes%204%21%7D%3D%5Cfrac%7B4%21%20%5Ctimes%205%20%5Ctimes%206%7D%7B2%20%5Ctimes%204%21%7D%3D%5Cfrac%7B5%20%5Ctimes%206%7D%7B2%7D%3D%5Cfrac%7B30%7D%7B2%7D%3D15)
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.
The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
![P=\frac{60}{120}=\frac{1}{2}=50\%](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B60%7D%7B120%7D%3D%5Cfrac%7B1%7D%7B2%7D%3D50%5C%25)
The probability is 1/2, or 50%.
Answer:
1107.6
Step-by-step explanation:
1420x.22 =312.4
1420-312.4=1107.6
Answer:
The maximum height is 784 feet
Step-by-step explanation:
In this problem we use the kinematic equation of the height h of an object as a function of time
![h(t) = -16t ^ 2 + v_0t + h_0](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%20%5E%202%20%2B%20v_0t%20%2B%20h_0)
Where
is the initial velocity and
is the initial height.
We know that
![v_0 = 192\ \frac{ft}{sec}](https://tex.z-dn.net/?f=v_0%20%3D%20192%5C%20%5Cfrac%7Bft%7D%7Bsec%7D)
Then the equation of the height is:
![h(t) = -16t ^ 2 + 192t +208](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%20%5E%202%20%2B%20192t%20%2B208)
For a quadratic function of the form ![ax ^ 2 + bx + c](https://tex.z-dn.net/?f=ax%20%5E%202%20%2B%20bx%20%2B%20c)
where
the maximum height of the function is at its vertex.
The vertice is
![x = -\frac{b}{2a}\\\\y = f(\frac{-b}{2a})](https://tex.z-dn.net/?f=x%20%3D%20-%5Cfrac%7Bb%7D%7B2a%7D%5C%5C%5C%5Cy%20%3D%20f%28%5Cfrac%7B-b%7D%7B2a%7D%29)
In this case
![a = -16\\b = 192\\c = 208](https://tex.z-dn.net/?f=a%20%3D%20-16%5C%5Cb%20%3D%20192%5C%5Cc%20%3D%20208)
Then the vertice is:
![t = -\frac{192}{2(-16)}\\\\t = 6\ sec](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B192%7D%7B2%28-16%29%7D%5C%5C%5C%5Ct%20%3D%206%5C%20sec)
Now we calculate h (6)
![h(6) = -16(6) ^ 2 +192(6) +208\\\\h(6) = 784\ feet](https://tex.z-dn.net/?f=h%286%29%20%3D%20-16%286%29%20%5E%202%20%2B192%286%29%20%2B208%5C%5C%5C%5Ch%286%29%20%3D%20784%5C%20feet)
The maximum height is 784 feet
The answer is between 23 through 2. dont want to give the answer up :D hope this helps