Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
They show the decomposition of a multiplication expression into smaller parts
Answer:
just add 2.5 to Lin's distance and 3 to Andre's distance. eventually you will reach a point where their values are the same. Then the hour next to it is the answer you are looking for
Step-by-step explanation:
Let (x,y) be an arbitrary point on the circle.
Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]
Since x2 + y2 = 1, y2 = 1-x2.
So, d = √[x2 - 6x + 9 + 1 - x2]
d = √(-6x+10)
Domain: x is the x-coordinate of a point on the circle centered at (0,0) with radius 1. So, -1≤x≤1.
But, for d to be defined, we need -6x+10 ≥ 0. So, x ≤ 5/3 (True for all x in [-1,1]).
Domain = [-1,1]
Range: -1 ≤ x ≤ 1 So, 6 ≥ -6x ≥ -6
16 ≥ -6x+10 ≥ 4
4 ≥ √(-6x+10) ≥ 2 That is, 2 ≤ d ≤4
Range: [2,4]
Step-by-step explanation:
