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zalisa [80]
3 years ago
13

P= (x,y) is an arbitrary point on the circle x^2+y^2=36

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Let (x,y) be an arbitrary point on the circle.

Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]

Since x2 + y2 = 1, y2 = 1-x2.

So, d = √[x2 - 6x + 9 + 1 - x2]

     d = √(-6x+10)

Domain:  x is the x-coordinate of a point on the circle centered at (0,0) with radius 1.  So, -1≤x≤1.

             But, for d to be defined, we need -6x+10 ≥ 0.  So, x ≤ 5/3  (True for all x in [-1,1]).

             Domain = [-1,1]

Range:    -1 ≤ x ≤ 1   So, 6 ≥ -6x ≥ -6

                                    16 ≥ -6x+10 ≥ 4

                                     4 ≥ √(-6x+10) ≥ 2   That is, 2 ≤ d ≤4

              Range:  [2,4]

Step-by-step explanation:

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Answer:

-3 1/3

Step-by-step explanation:

The quadratic

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Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.

To find the minimum value, we need to evaluate the function for x=2/3.

The most straightforward way to do this is to substitue 2/3 for x.

... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2

... y = (4 -8 -6)/3 = -10/3

... y = -3 1/3

_____

<em>Confirmation</em>

You can also use a graphing calculator to show you the minimum.

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Read 2 more answers
Use cubic regression to find a function that fits the following points.
olasank [31]

Answer:

The cubic regression that fits the points (x,y) =(-2,-16), (x,y) = (1,5), (x,y) = (3, 59) and (x,y) =(6,440) is y =2\cdot x^{3}+x+2.

Step-by-step explanation:

A cubic polynomial is a polynomial that has the following form:

y = a\cdot x^{3}+b\cdot x^{2}+c\cdot x + d (1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c, d - Coefficients, dimensionless.

We construct the following system of equations to determine the coefficients of the cubic regression:

(x,y) =(-2,-16)

-8\cdot a +4\cdot b -2\cdot c + d = -16 (1)

(x,y) = (1,5)

a+b+c+d= 5 (2)

(x,y) = (3, 59)

27\cdot a + 9\cdot b + 3\cdot c + d = 59 (3)

(x,y) =(6,440)

216\cdot a + 36\cdot b + 6\cdot c + d = 440 (4)

The solution of the system of linear equations is:

a = 2, b = 0, c = 1, d = 2

The cubic regression that fits the points (x,y) =(-2,-16), (x,y) = (1,5), (x,y) = (3, 59) and (x,y) =(6,440) is y =2\cdot x^{3}+x+2.

7 0
3 years ago
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