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Umnica [9.8K]
3 years ago
13

Solve each system of linear equations by substitution ​

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

x=-6-3y/2

Step-by-step explanation:

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Which pair of numbers is relatively prime?
kondor19780726 [428]

Answer:

B

Step-by-step explanation:

Two numbers are relatively prime when there is no integer greater than one that that is a factor of both of them.

A: 15 and 21 both have a factor of 3.

<u>B</u>: 24 and 49 have no common factors, and therefore, are relatively prime.

C. 35 and 135 both have a factor of 5.

D:  45 and 102 both have a factor of 3.

6 0
3 years ago
Jaylen earns $4250 each month at his job. At this rate, how much will he
dezoksy [38]

Answer:

<u>C. 76,500</u>

Step-by-step explanation:

<h2>18 months in 1 \frac{1}{2} years.</h2><h2>4250 x 18 = 76,500</h2>
4 0
2 years ago
•Use the Pythagorean Theorem c^6 = a2+ b2 •Show you work to find each missing side •
zhannawk [14.2K]

Answer:

hypotenuse = 10

Step-by-step explanation:

If you can tell at first glance it is a 3,4,5 triangle (6,8,10)/2=(3,4,5). Then you know that c has to equal 5.

If not,

a^2+b^2=c^2

6^2+8^2=c^2

36+64=c^2

100=c^2

10=c

6 0
3 years ago
Reduce this algebraic fraction. y^3 -3y^2+y-3 / y^2-9
blondinia [14]

Answer:

y³ - 3y² + 1/y+3

Step-by-step explanation:

y² - 9 = (y - 3) ( y + 3)

y-3/(y-3)(y+3) = 1/y+3

6 0
3 years ago
Read 2 more answers
At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equatio
andriy [413]

The correct format of the question is

At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. P = 400 ( 1.2 )^ t Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?

(A) 291

(B) 691

(C) 1040

(D) 1440

Answer:

The increase in the population at the end of 2009 is 291 people

Step-by-step explanation:

We are given the equation as P = 400 ( 1.2 )^ t

where

P = No of People

t= No of Years

it is given that in the year 2006 the population is 400

this will only happen when we take t= 0

so for

Year    value of t

2006-    t = 0

2007-    t  = 1

2008-    t = 2

2009     t = 3

No of people in 2009 will be

P = 400(1.2)^3

     = 400*1.728

   P  = 691.2

Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691

Increase = P(2009) - P(2006)

               = 691 - 400

                = 291

The increase in the population at the end of 2009 is 291 people.

4 0
3 years ago
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