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Zolol [24]
3 years ago
7

3x(x-2) = 0 in standard form and its roots

Mathematics
1 answer:
slava [35]3 years ago
6 0

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

3x(x−2)=0

Step 1: Simplify both sides of the equation.

3×2−6x=0

For this equation: a=3, b=-6, c=0

3×2+(−6x)+0=0

Step 2: Use quadratic formula with a=3, b=-6, c=0.

x=\frac{-b ±\sqrt{b^2-4ac} }{2a}

x=2 or x=0

hope it helps other wise I am sorry

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What type of triangle is formed by joining the points D(7, 3), E(8, 1), and F(4, -1)?
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D(7,3) \\
E(8,1) \\
F(4,-1)

The lengths of the sides of the triangle:
\overline{DE}=\sqrt{(8-7)^2+(1-3)^2}=\sqrt{1^2+(-2)^2}=\sqrt{1+4}=\sqrt{5} \\ \\
\overline{DF}=\sqrt{(4-7)^2+(-1-3)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5 \\ \\
\overline{EF}=\sqrt{(4-8)^2+(-1-1)^2}=\sqrt{(-4)^2+(-2)^2}=\sqrt{16+4}=\sqrt{20}= \\
=\sqrt{4 \times 5}=2\sqrt{5}

No sides are equal to each other, so it's a scalene triangle.

Check if the sides satisfy the Pythagorean theorem:
(\sqrt{5})^2 + (2\sqrt{5})^2=5^2 \\
5+20=25 \\
25=25 \\
true
They do, so it's a right triangle.

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