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Gnom [1K]
3 years ago
12

Find the distance between parallel lines whose equations are y = x - 6 and y = x + 8.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Distance between y2 = x + 8 and y1 = x - 6

y2 - y1 = (x + 8) - (x - 6) = 14

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HELP!!!
marusya05 [52]
The equation of an ellipse is x²/a²  + y²/b² =1

a being the distance between the center & x intercept =7
b being the distance between the center & y intercept =5

Hence the equation of this ellipse is:

x²/49 + y²/25 =1
3 0
3 years ago
Select the correct answer
Rama09 [41]

Answer:

option c

Step-by-step explanation:

6 0
3 years ago
What is (3*7) divided by 5
oksano4ka [1.4K]

Answer:

The answer is 4.2,

Hope that helped. x

Step-by-step explanation:

3 x 7 (3*7) = 21

21 divided by 5 = 4.2.

8 0
2 years ago
Read 2 more answers
Kevin plants a total of 72 flower in equal rows. He plants 6 rows of of yellow flowers and 2 rows of red flowers. How any flower
Ber [7]

Answer: 36

Step-by-step explanation: 72/6= 36

72/2= 37

4 0
3 years ago
Suppose that the distance an aircraft travels along a runway before takeoff is given by D=(5/3)t^2, where D is measured in meter
ArbitrLikvidat [17]

Answer:

It will take 90s for the aircraft to become airbone.

In that time, the aircraft will have traveled 13500m = 13.5km.

Step-by-step explanation:

The velocity function is the derivative of the distance function.

In this problem, we have the following distance function:

D(t) = \frac{5t^{2}}{3}

So the speed function is the following:

S(t) = \frac{10t}{3}

The aircraft will become airborne when its speed reaches 300km/h. How long will it take to become airborne?

This is going to happen when S(t) = 300. So:

S(t) = \frac{10t}{3}

\frac{10t}{3} = 300

t = 90

It will take 90s for the aircraft to become airbone.

What distance will it travel in that time?

This is D(t) when t = 90. So:

D(t) = \frac{5t^{2}}{3}

D(90) = \frac{5*90^{2}}{3} = 13500

In that time, the aircraft will have traveled 13500m = 13.5km.

7 0
3 years ago
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