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Gnom [1K]
3 years ago
12

Find the distance between parallel lines whose equations are y = x - 6 and y = x + 8.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Distance between y2 = x + 8 and y1 = x - 6

y2 - y1 = (x + 8) - (x - 6) = 14

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Expand the logarithm. log4 (3xyz​)^2
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Read 2 more answers
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
Please someone help me with this!
Olenka [21]

Answer:

<u>Please read the answer below.</u>

Step-by-step explanation:

<u>Question 2. 25% of what number is 30?</u>

25% - Whole 30, 50% Whole 60, 75% Whole 90, 100% Whole 120

<u>Question 3. What operation did you use the find the whole?</u>

In the previous question, I found the whole, adding 30 to the previous value.

For example, I added 30 to 30 and calculate 60. To 60 then i added 30 to get 90 and added 30 to get 120 because in this question, all the 4 parts were exactly the same size (30).

<u>Question 4. What are you multiplying/dividing? Do you use the percent or something else?</u>

In the specific case of question 2, I noticed that the size of the parts were exactly the same, using it for calculating the whole. If 1 part out of 4 is 30, then 2 parts or 50% are 60, 3 parts or 75% are 90 and then 4 parts of 100% are the whole I'm being asked, in this case, 120.

3 0
3 years ago
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