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Gnom [1K]
3 years ago
12

Find the distance between parallel lines whose equations are y = x - 6 and y = x + 8.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Distance between y2 = x + 8 and y1 = x - 6

y2 - y1 = (x + 8) - (x - 6) = 14

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3 0
3 years ago
Read 2 more answers
21 points!!
Bogdan [553]

Answer:

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: f(x) = C+ A sinBx and f(x) = C + A cosBx. A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or \frac{2\pi}{|B|}. C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is \frac{2\pi}{|2|}=\pi

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

3 0
3 years ago
The first one is it right or wrong?
gayaneshka [121]
The first one is wrong

(do you need help solving it?)
3 0
3 years ago
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