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kolbaska11 [484]
3 years ago
6

HURRY I NEED HELP I JUST NEED TO KNOW HOW TO DO THIS PLEASE ILL GIVE 5 STARS AND STUFF PLS

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

On the left, it would be + 1 for each blank, and on the right it would also be +1 for each blank.

Step-by-step explanation:

They are asking for the intervals between each number.

Hope this helps!

You might be interested in
Which number best represents Point Q on the number line below?
Bumek [7]

Answer:

<em>D. 3.5!</em>

Step-by-step explanation:

If you slowly go up the line it will be 0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, if it were to carry on it would keep being .5 then the next number. Since this is not a fraction number line the answer is not A. -9/2 nor C. -7/2.

<u><em>~ LadyBrain</em></u>

6 0
3 years ago
I need help on these two questions please
Simora [160]

Answer:

<h2>For #1=     D = 24.25</h2><h2>     #2=       D= 21</h2>

Step-by-step explanation:

hope this helps. pls mrk me branliest :)

4 0
3 years ago
Read 2 more answers
Which graph shows the solution to the inequality -3x-7x&lt;20
hjlf
A graph of this inequality would be a number line, with the number -2 circled (not filled in), and the number line to the right of -2 shaded.

To solve this, you will combine like terms first:

-3x-7x < 20
-10x < 20

Divide both sides by -10:
-10x/-10 < 20/-10

When you divide an inequality by a negative number, you flip the inequality symbol:

x > -2
5 0
4 years ago
I DON'T KNOW WHAT TO DO WITH THIS. HELP
mixas84 [53]
Ok, so since she spent $15 each week for 10 weeks, she spent a total of $150 over those 10 weeks. The best approach I would use for this is cross multiplication. The total percentage of Books and music would be 35% out of 100% because 10+25=35. The answer is b, 50.

Hope this helps :)
6 0
4 years ago
Please help me thank you.
Alona [7]

Answer:

\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}

\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}

Step-by-step explanation:

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x

8 0
3 years ago
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