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3 years ago

Solve. the square root of 44-2x = x-10

2 answers:

5 0

44-2x=x-10 subtract 44 from both sides -2x= x-54 subtract x from both sides -3x= -54 divide by -3 x= 18 square root of 18= 4.24 in radical form 3 square root of 2 hope this helps

Elza [17]3 years ago

5 0

Sqrt(44 - 2x) = x - 10
44 - 2x = (x - 10)^2 = x^2 - 20x +100
0 = 1x^2 - 18x + 66
yikes! quadratic formula
ax^2 + bx + c = 0
a = 1
b = -18
c = 66
x = [-b ± sqrt(b^2 - 4ac)]/(2a)
x = [18 ± sqrt((-18)^2 - 4(1)(66))]/(2(1))
x = 12.873 or 5.127

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Step-by-step explanation:

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3 years ago

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3 years ago

XLiV represents 64 true ya false

V125BC [204]

Answer:

False

Step-by-step explanation:

Given

$XLIV = 64$

Required

True or False

The above numeral can be split as follows:

$XLIV = XL + IV$

X means 10 and L means 50.

But because X (10) which is smaller comes before L (50), XL is executed as:

$XL = -10 + 50$

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Substitute 40 for XL and 4 for IV.

$XLIV = 40 + 4$

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Hence;

$XLIV = 64$ is false

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2 years ago

Help please! I’m giving brainliest to however gets this question right.

Arisa [49]

Answer:

They both have area 4

Step-by-step explanation:

Area of the square:

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Area of the triangle:

Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:

$\frac{1}{2}base*height$

$\frac{1}{2}4\sqrt2*\sqrt2=4$

We know the length of the diagonal is $\sqrt2$ as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.