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gizmo_the_mogwai [7]
3 years ago
6

Solve. the square root of 44-2x = x-10

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
5 0
44-2x=x-10 subtract 44 from both sides -2x= x-54 subtract x from both sides -3x= -54 divide by -3 x= 18 square root of 18= 4.24 in radical form 3 square root of 2 hope this helps
Elza [17]3 years ago
5 0
Sqrt(44 - 2x) = x - 10
44 - 2x = (x - 10)^2 = x^2 - 20x +100
0 = 1x^2 - 18x + 66
yikes! quadratic formula
ax^2 + bx + c = 0
a = 1
b = -18
c = 66
x = [-b ± sqrt(b^2 - 4ac)]/(2a)
x = [18 ± sqrt((-18)^2 - 4(1)(66))]/(2(1))
x = 12.873 or <span>5.127</span>
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Step-by-step explanation:

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According to the given question.

We have an equation

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So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}

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Multiply both the sides by x.

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Again multiply both the sides by x

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\implies 5x^{2} -2x^{2} +18x +2x +12 = 0

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Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

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Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

brainly.com/question/2976807

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