Answer:
x=2
Step-by-step explanation:
10x+4=2x+20
10x-2x=20-4
8x=16
x=2
5(x-1) + 3 = 13
5x - 5 + 3 = 13
5x -2 = 13
5x = 15
x = 15/5
x = 3
Answer:
m∠EAE ' = m∠FAF '
Step-by-step explanation:
Rotation is a type of transformation referred to a in which the shape of the original object is preserved and the angle of rotation is constant for all the parts of the body.
Thus, when ΔDEF rotates 90° clockwise about point A to create ΔD 'E 'F.
Answer:
Name: Circle A
Chords: Chord DP, Chord HC
Tangent: EFG
Step-by-step explanation:
Name a circle by the center, in this case it's A.
Chord: A chord is a line only in the circle, not outside of it, and its endpoints are right on the circle.
Tangent of a circle: "Tangent" means touching, and this is a line, in terms of a circle, that touches the circle but is not INSIDE of the circle.
Answer:
1. 625,000 J
2. 100 J
4. 5 kg
5. √5 ≈ 2.236 m/s
Step-by-step explanation:
You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².
To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.
In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.
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1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J
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2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J
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4. KE = (1/2)<em>m</em>v²
250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²
(250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg
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5. KE = (1/2)<em>m</em>v²
2000 kg·m²/s² = (1/2)(800 kg)v²
(2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²
v = √5 m/s ≈ 2.236 m/s