A) (x+3)² b) (x-4)² c) (3+2x) (3-2x) d) (x+2)³ e) x³-8

How do i find the slope

erastova [34]

Answer:

the slope is x 0 y-9

Step-by-step explanation:

very very very sorry if it's wrong I apologize

8 0

3 years ago

Read 2 more answers

Given: sin(18m-12)=cos(7m+2), find the value of m.

V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0

3 years ago

Gareth 30 students in a class and the ratio of boys to girls in the class is 2:3 calculate the number of goals

pishuonlain [190]

Answer:

There are 12 boys and 18 girls

Step-by-step explanation:

Equations

There are 30 students in a class. Let's call:

x = number of boys

Since the sum of boys and girls is 30:

30 - x = number of girls

The ratio of boys to girls is 2:3, thus:

$\displaystyle \frac{x}{30-x}=\frac{2}{3}$

Crossing denominators:

3x = 2(30 - x)

Operating the parentheses:

3x = 60 - 2x

Adding 2x:

5x = 60

Dividing by 5:

x = 60/5 = 12

x = 12

There are 12 boys and 30-12=18 girls

8 0

3 years ago

6) Sally wrote the number 30, 048 in expanded form.

vichka [17]

Answer:

the answer is G) Change 30 to 3,000

6 0

3 years ago

The base of a solid in the first quadrant of the xy plane is a right triangle bounded by the coordinate axes and the line x + y

Ivahew [28]

The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is

(x - x^2)^2 * sqrt(3)/4.

Integrating from x = 0 to x = 1, we have

[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4

= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.

Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...

8 0

3 years ago