No hay ninguno de los nimbers que no pertenezca a la secuencia.
<h3>¿Qué número no pertenece a la secuencia?</h3>
Sabemos que una secuencia tiene que ver con un arreglo de números en un orden definido. Todos los números en una secuencia deben tener la misma razón común o diferencia común.
Si miramos todos los números que están escritos en la secuencia, la diferencia común aquí es seis. Se sigue entonces que todos los números son parte de la sucesión y no hay ninguno de los números que no pertenezca a la sucesión.
Obtenga más información sobre la secuencia: brainly.com/question/21961097
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Answer:
D. Open the compass so that the distance from the two points of the compass is wider than half the length of 
.
Step-by-step explanation:
To construct a perpendicular for , we must first take a compass & take the distance of its arms wider than half the length of .
This is done in order to get two intersecting arcs in the top & bottom of so that a perpendicular bisector can be drawn through it.
After two intersecting lines are drawn below & above , draw a line joining these 2 points through their points of intersection. The point where it intersects is the middle-most point of & now a perpendicular bisector of is constructed.
Answer: C
Step-by-step explanation:
If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.
Hope this helped you and made sense! Feel free to ask me any questions you have!
Step-by-step explanation:
The ratio of the perimeters = the scale
P₂ / P₁ = 6 / 4 = 3 / 2
The ratio of the areas = the square of the scale
A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4
Same for the triangles:
P₂ / P₁ = 6 / 3 = 2
A₂ / A₁ = (6 / 3)² = (2)² = 4
