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andrezito [222]

2 years ago

9

What is a variable that cannot be controlled?

1 answer:

s344n2d4d5 [400]2 years ago

7 0

Constant. A constant variable can not be controlled, or manipulated in any way.

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I’ll give points and brainalist for a correct answer / explanation

wlad13 [49]

Answer:

Answer is C

r= 3

there are 4 circles.

total area of circle = 4 π 3²

so shaded area = 12²- 4π3²= 30.90

Step-by-step explanation:

3 0

2 years ago

Sam has 4 gallons of juice. Each glass holds 1/5 of a gallon . How many glasses can he fill

Softa [21]

Answer:

20

Step-by-step explanation:

Divide 4 by 1/5 in decimal form, 1/5 in decimal form is 0.20. You can get the decimal form by dividing 1 by 5.

So 4/0.20 = 20.

6 0

3 years ago

In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting

laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

$E= z^*\dfrac{\sigma}{\sqrt{n}}$

, where n= sample size.

$\sigma$ = Population standard deviation

z*= Critical value(two-tailed).

As per given , we have

$\overline{x}=1438$

n= 35

$\sigma=269$

For 98% confidence , the significance level = $1-0.98=0.02$

By z-table , the critical value (two -tailed) = $z^* = z_{\alpha/2}=z_{0.01}=2.326$

Now , the maximum error = $E= (2.326)\dfrac{269}{\sqrt{35}}$

$E= (2.326)\dfrac{269}{5.9160797831}$

$E= (2.326)\times45.4692989044=105.761589252\pprox105.76$

Hence, With 98% confidence level , the maximum error = $105.76.

4 0

2 years ago

An alternating current E(t)=120sin(12t) has been running through a simple circuit for a long time. The circuit has an inductance

Dvinal [7]

Answer:

14.488 amperes

Step-by-step explanation:

The amplitude I of the current is given by

$\large I=\displaystyle\frac{E_m}{Z}$

where

$\large E_m$ = amplitude of the energy source E(t).

Z = Total impedance.

The amplitude of the energy source is 120, the maximum value of E(t)

The total impedance is given by

$\large Z=\sqrt{R^2+(X_L-X_C)^2}$

where

<em> R= Resistance </em>

<em>L = Inductance </em>

<em>C = Capacitance </em>

<em>w = Angular frequency </em>

$\large X_L=wL$ = inductive reactance

$\large X_C=\displaystyle\frac{1}{wC}$ = capacitive reactance

As E(t) = 120sin(12t), the angular frequency w=12

So

$\large X_L=12*0.37=4.44\\\\X_C=1/(12*7)=0.012$

and

$\large Z=\sqrt{7^2+(4.44-0.012)^2}=8.283$

Finally

$\large I=\displaystyle\frac{E_m}{Z}=\frac{120}{8.283}=14.488\;amperes$

7 0

2 years ago

Geometry Question Please Help!!!!

lora16 [44]

The equation of a parabola is given by $f(x)=a(x-h)^{2}+k$ where $(h,k)$ is the vertex.

We have the vertex is (-3,-2) so we have $h=-3$ and $k=-2$

Substituting -3 and -2 into the $f(x)$
$f(x)=a(x--3)^{2}+(-2)$
$f(x)=a(x+3)^{2}-2$

Hence, the correct answer is option D

5 0

2 years ago