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Olegator [25]
3 years ago
7

6.3 + 6.4 + 9.4 what is the sum of?

Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

22.1

You can search for any mathematical expression, using functions such as: sin, cos, sqrt, etc. You can find a complete list of functions here.

Rad

Deg

x!

Inv

sin

ln

π

cos

log

e

tan

√

Ans

EXP

xy

(

)

%

AC

7

8

9

÷

4

5

6

×

1

2

3

−

0

.

=

+

tekilochka [14]3 years ago
6 0

Answer:

22.1

Step-by-step explanation:

there is your answer have a great day

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A company sells boxes of duck calls (d) for $35 and boxes of turkey calls (t) for $45. they make batches of duck calls that fill
SIZIF [17.4K]

Answer:

Option A is the correct choice.

Step-by-step explanation:

Let d be the number of boxes of duck calls and t be the number of boxes of turkey calls.

We have been given that a company sells boxes of duck calls for $35 and boxes of turkey calls (t) for $45, so the revenue earned from selling d boxes of duck and t boxes of turkey call will be 35d and 45t respectively.

Further, the company plan to make $300. We can represent this information as:

35d+45t=300...(1)

We are also told that they make batches of duck calls that fill 6 boxes and batches of turkey calls that fill 8 boxes. the company only has 42 boxes. We can represent this information as:

6d+8t=42...(2)

6d=42-8t...(2)

Therefore, our desired system of equation will be:

35d+45t=300...(1)

6d=42-8t...(2)  


8 0
3 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
Suppose you are given Circle B with Area of ΔAOB(purple) = Area of Sector BOC (pink). What is m
Art [367]
\bold{ANSWER:}

28.65 Degrees

\bold{EXPLANATIONS:}

8 0
2 years ago
Nicolas says that (2^6)(2^6) equals 2^12 and also equals 4^6 . Do you agree?
alex41 [277]

Answer:

Nicolas is correct.

4^6 =4096

2^12 = 4096

4 0
3 years ago
Solve the problem below:<br><br><br> ty :P
Leviafan [203]

Answer:

-3

Step-by-step explanation:

rise/run

-\frac{6}{2} or -\frac{3}{1}  which is equal to -3

<em>good luck, hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
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