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Blizzard [7]
2 years ago
5

Solve the math problem No spamming

Mathematics
1 answer:
valkas [14]2 years ago
8 0

Answer:

1. slope for pq is 150 / 3 but simplified is 50/1

2. 200

3. 4

Step-by-step explanation:

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Please answer this correctly
Illusion [34]

Answer:

$15.50

Step-by-step explanation:

0.5 (1) + 5 (3)

0.5 + 15

15.50

7 0
3 years ago
WILL GIVE BRAINLIEST
frez [133]

Answer:

She will make a profit of one dollar because the cost of operation and production is 203 dollars in total and selling 17 necklaces she will make 204 dollars

Edit: b) She will need to sell exactly seventeen necklaces

Step-by-step explanation: Hope this helps!

5 0
3 years ago
Evaluate the difference quotient for the function
Alexeev081 [22]

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my pp is bigger than the holocaust

Step-by-step explanation:

4 0
3 years ago
Please help! Correct answer only! This assignment is due today.
vichka [17]

Answer:

  0.2601

Step-by-step explanation:

There are 19C16 = 969 ways for Lester to choose 16 of the 19 objects.

There are 12C11 = 12 ways to choose 11 vases, and 7C5 = 21 ways to choose a non-vase, for a total of (12)(21) = 252 ways to choose exactly 11 vases in 16 objects.

So, the probability of interest is ...

  252/969 ≈ 0.2601

_____

nCk = n!/(k!(n-k)!) ... the number of ways to choose k objects from n

5 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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