1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blizzard [7]
2 years ago
5

Solve the math problem No spamming

Mathematics
1 answer:
valkas [14]2 years ago
8 0

Answer:

1. slope for pq is 150 / 3 but simplified is 50/1

2. 200

3. 4

Step-by-step explanation:

You might be interested in
John is 36 years old now. 1/4 of his age is equal to 1/3 of sam's age. find their total age in 5 years time
sveticcg [70]

Answer:

John = 41 years

Sam = 32 years

Step-by-step explanation:

7 0
2 years ago
PLEASE HURRY!! -2n=24 WHAT IS N?
Alja [10]

Answer:

n = -12

Step-by-step explanation:

plug -12 in for n and its -2 x -12 which equals 24

7 0
3 years ago
Read 2 more answers
Reliance on solid biomass fuel for cooking and heating exposes many children from developing countries to high levels of indoor
kherson [118]

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.314, 3.486)

95% confidence interval for the population mean PEF for children in LPG households

= (4.195, 4.365)

Simultaneous confidence interval for both = (3.314, 4.365)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

z-critical value for 95% confidence level = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.40

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 756

σₓ = (1.20/√756) = 0.04364

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.40 ± (1.960 × 0.04364)

CI = 3.40 ± 0.08554

95% CI = (3.31446, 3.48554)

95% Confidence interval = (3.314, 3.486)

For the children in the LPG households

Sample mean = 4.28

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.19

N = sample size = 752

σₓ = (1.19/√752) = 0.043395

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.28 ± (1.960 × 0.043395)

CI = 4.28 ± 0.085054

95% CI = (4.1949, 4.3651)

95% Confidence interval = (4.195, 4.365)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.40

n₁ = 756

s₁ = 1.20

μ₂ = 4.28

n₂ = 752

s₂ = 1.19

σ = √[(1.20²/756) + (1.19²/752)] = 0.061546

z = (3.40 - 4.28) ÷ 0.061546 = -14.30

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -14.30, at 0.01 significance level, with a one tailed condition) = 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 756

σₓ = (0.5/√756) = 0.018185

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.018185)

CI = 2.30 ± 0.03564

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

3 0
3 years ago
How do you find total bill for simple interest
stepan [7]

Answer:

I=Prt,  I=simple interest, P=principal (starting amount), r=interest as a decimal, t =number of times the interest is paid or "time"

For example the simple interest earned on a $1000 deposit earning 4% APR for ten years is:

I=1000(.04)10

I=$400.00

Step-by-step explanation:

8 0
3 years ago
Help me thanks please thanks
Gnesinka [82]
83838383 centimeters
4 0
3 years ago
Read 2 more answers
Other questions:
  • Use distributive property to remove the parenthesis:<br> 7(w-6)
    14·2 answers
  • 1,025 = ( X × 9) + 17
    5·1 answer
  • Seven times the sum of 5 and a number amount to 91. Find the number
    15·2 answers
  • The data set shows the weights of pears, in grams, in a crate of fruit. 143, 146, 158, 159, 162, 166, 169, 170, 170, 193, 197 Wh
    12·2 answers
  • What a ratio of 4 days to 36 hours​
    15·1 answer
  • NEED HELP ASAP please
    8·2 answers
  • About how long will it take Karen’s investment to double if it earns 18% interest compounded annually? A. 4 years B. 5 years C.
    10·1 answer
  • X-3 / 4 = x/2 <br><br> please shows the steps :)
    11·1 answer
  • What is 3.5% of 3,000
    11·2 answers
  • answer me please as soon as possible plot the graph same as shown in the question using green orange and black colors
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!