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Firdavs [7]
4 years ago
13

Determine the quadratic function f whose graph is given. The vertex is (1,-3) and y-intercept is -2

Mathematics
1 answer:
Nesterboy [21]4 years ago
5 0

Answer:

Vertex form: f(x)=(x-1)^2-3

Standard form: f(x)=x^2-2x-2

Step-by-step explanation:

A quadratic function in vertex form is f(x)=a(x-h)^2+k where (h,k) is the vertex.

We are given h=1,k=-3.

Let's plug that in:

f(x)=a(x-1)^2-3.

Now let's find a.

We will use the y-intercept (0,-2) to find a.

f(0)=a(0-1)^2-3

-2=a(0-1)^2-3

-2=a(-1)^2-3

-2=a(1)-3

-2=a-3

1=a

So the function in vertex form is:

f(x)=(x-1)^2-3.

In standard form, we will have to multiply and combine any like terms.

Let's do that:

f(x)=(x-1)(x-1)-3

f(x)=x^2-x-x+1-3

f(x)=x^2-2x-2

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