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Firdavs [7]
4 years ago
13

Determine the quadratic function f whose graph is given. The vertex is (1,-3) and y-intercept is -2

Mathematics
1 answer:
Nesterboy [21]4 years ago
5 0

Answer:

Vertex form: f(x)=(x-1)^2-3

Standard form: f(x)=x^2-2x-2

Step-by-step explanation:

A quadratic function in vertex form is f(x)=a(x-h)^2+k where (h,k) is the vertex.

We are given h=1,k=-3.

Let's plug that in:

f(x)=a(x-1)^2-3.

Now let's find a.

We will use the y-intercept (0,-2) to find a.

f(0)=a(0-1)^2-3

-2=a(0-1)^2-3

-2=a(-1)^2-3

-2=a(1)-3

-2=a-3

1=a

So the function in vertex form is:

f(x)=(x-1)^2-3.

In standard form, we will have to multiply and combine any like terms.

Let's do that:

f(x)=(x-1)(x-1)-3

f(x)=x^2-x-x+1-3

f(x)=x^2-2x-2

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The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3><u>Solution:</u></h3>

Given equation is 5x - 3y = 15

<em><u>To find: x - intercept and y -intercept</u></em>

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

<em><u>Finding x - intercept:</u></em>

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

<em><u>Finding y - intercept:</u></em>

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

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Step-by-step explanation:

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