A culture of 2.4 × 10^11 bacteria is in a Petri dish A
A culture of 8 × 10^9 bacteria is in Petri dish B
Number of times number of bacteria in Petri dish A is greater than that number in Petri dish B:
Divide 2.4 by 8 to give 0.3
Divide 10^11 by 10^9 to give 10^(11-9) = 10^2
The answer is 0.3 × 10²
Answer:
10.) y = -5x + 7
12.) y = 3/2x - 8
Step-by-step explanation: Since you have to create a new line that us parallel, the slopes will be equivalent. So the mx value will not change. Now we can plug in the coordinates to find the value of b.
10.)
2 = -5(1) + b.
2 = -5 +b
b = 7
therefore...
y = -5x + 7
12.)
2(-5) = 3(2) + b
-10 = 6 + b
b = -16
therefore...
2y = 3x - 16
simplified:
y = 3/2x - 8
We know that pupils are students
Students = S
boys = B
Teachers = T
So....
S = 8T
Boys = 3G
T = B - 70
Since there is 8x students than teachers, I did Boys = 6x and girls = 2x
I'm going to use this next: S = 8T
8x = 8(B -70)
8x = 8(6x - 70)
8x = 4x - 560
x = 14
We know there is 8x students, so there are 112 students and we know that there is 1/8 of teachers, so there are 14 teachers.
Answer = 126.
Answer: the no.s are-
2.472
-6.472
Step-by-step explanation:
xy=24-----1
x+y=-4------2
from 2 we get x=-4-y
sustituting=
into 1 we get
quadratic eq = y^2 + 4y + 24=0
so
-4+- root 16-96/2
thus on further solving we get -2 +-4.472
on adding= -2+4.472= 2.472
on subtraction= -2 -4.472= -6.472
