9514 1404 393
Answer:
F
Step-by-step explanation:
If the circle is tangent to the x-axis at 4, the center lies on the line x=4.
If the circle is tangent to the y-axis at 4, the center lies on the line y=4.
If the center of the circle is (x, y) = (4, 4) and it is tangent to the axes, then the radius is 4.
The standard-form equation of the circle centered at (h, k) with radius r is ...
(x -h)² +(y -k)² = r²
For the values (h, k) = (4, 4) and r = 4, the equation is ...
(x -4)² +(y -4)² = 16 . . . . . . matches choice F
Answer:
x is 1 y is 1 and a is 1 hope this helped
Answer:
(0,2)
Step-by-step explanation:
solve by addition/elimination
2x + 3y= 6
–3x + 5y = 10
multiply first equation by 3 and second one by 2 to eliminate x)
6x+9y=18
-6x+10y=20 (add the two equations)
6x+9y-6x+10y=38
19y=38
y=38/19=2
2x+3y=6
2x=6-6
x=0
I need more information to be able to answer
Answer:
y = -8x -25
Step-by-step explanation:
The 2-point form of the equation of a line is useful when you are given 2 points.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (7 -(-1))/(-4 -(-3))(x -(-3)) +(-1)
y = 8/-1(x +3) -1
y = -8x -25
