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hoa [83]
3 years ago
5

d="TexFormula1" title="g(t) = {t}^{3} + {2t}^{2} - 10t - 8" alt="g(t) = {t}^{3} + {2t}^{2} - 10t - 8" align="absmiddle" class="latex-formula">
write the polynomial in factored form as a product of linear factors​
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

Step-by-step explanation:

for example

We have to write the polynomial P(x) = 5x^3 -2x^2 + 5x - 2 as a product of linear factors.

P(x) = 5x^3 -2x^2 + 5x - 2

=> P(x) = x^2( 5x - 2) + 1( 5x - 2)

=> P(x) = (x^2 + 1)(5x - 2)

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I'm pretty there's a complement  

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Simplify this expression 3-(7a+1)
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3 - (7a + 1) =
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The digit in the tens placeof a two digit is three times that in the units place. if the digits are reversed , the new no will b
Charra [1.4K]

If a number's ten digit is x and the units digit is y, then you can write the number as 10x+y.

Obviously, inverting the digits would lead to the number 10y+x.

Since this new number is 36 less than the original, we have

10y+x = 10x+y-36 \iff 9x-9y=36\iff x-y=4

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3 years ago
Simplify<br> 3/the square root of 7
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Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form.
alexgriva [62]
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The equation for slope is (change in y)/(change in x), or y/x.
You can set up the equation like this;
[tex] m= \frac{y2-y1}{x2-x1}\\
m=\frac{10-5}{2-(-3)} \\
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So the slope of the line is 1.

To find the y-intercept, solve y = (1)x + b for b;
[tex] y=x+b\\
b=y-x [tex]
Plug the values of a point in for x and y;
[tex] b=10-2\\
b=8 [tex]

This brings your final equation to be [tex] y=x+8 [tex]. 
5 0
3 years ago
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