I believe the answer is 64?
I believe the answer is 4/5x +2. Sorry if I’m wrong.
There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Answer:
x = 16
y = 16 sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp/hyp
sin 60 = y/ 32
Multiply each side by 32
32 sin 60 = y
32 ( sqrt(3) /2) = y
16 sqrt(2)
cos theta = adj/ hyp
cos 60 = x /32
32 cos 60 = x
32 (1/2) =x
16 =x
Diagram? There is no diagram given.
a.
Cannot solve b without the diagram.
