V(t)=t^2+2t+1 integrating we get d(t)
d(t)=t^3/3+t^2+t or more neatly
d(t)=(t^3+3t^2+3t)/3 so
d(2)=(8+12+6)/3
d(2)=26/3
So the particle moves 9 feet (to the nearest foot) in the first two minutes.
Answer:
E) -4,7 and -2,8
Step-by-step explanation:
parallel lines have same slope
x - 2y = 16
y = 1/2 x -8 slope: 1/2
E. slope = Δy / Δx = (8-7) / (-2 - -4) = 1/2
Answer:

Step-by-step explanation:
Assume a pentagon has equal length where a be the side of the pentagon and r be the apothem of the pentagon.
Given:
Sides of pentagon 
apothem of pentagon 
The area of the pentagon formula is given below.

Where b = length of the base or side
And h = height of apothem
Now, we substitute side and apothem length in above formula.


Therefore, the area of the pentagon is 
Table B. The same input can't go to different outputs
56,000=5.6x10^4
Hope this helps :)