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2 years ago

Solve the inequality r 4-2(r-14)>0

Mathematics

1 answer:

klasskru [66]2 years ago

4 0

R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)

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zlopas [31]

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Step-by-step explanation:

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Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

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As $x$ gets arbitrarily large in magnitude, we find

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since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

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The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

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2 years ago

If f(x)=2x-6 and g(x)=3x+9, find (f+g)(x)

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A rectangular prism is shown below. What is the surface area, in square centimeters?

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174 square centimetres

Step-by-step explanation:

The formula for finding the surface area of a rectangular prism is

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Therefore surface area will be

= 2(11*5) + 2(11*2) +2(2*5)

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