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Radda [10]
3 years ago
8

Starts at 12 and ends at 6​

Mathematics
2 answers:
babymother [125]3 years ago
7 0
6 hours?
••••••••••••••
probably would be best to give more info
Oksanka [162]3 years ago
6 0

Answer:

126

Step-by-step explanation:

i don't know if it's correct or not

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The perimeter of a football field in a certain school is 296m. If the breadth is 2/3 of the length, find the sides of the field
MaRussiya [10]

Answer: 88.8 m , 59.2 m

Step-by-step explanation:

Given

Breadth is \frac{2}{3} of length

Suppose length is x m

So, breadth is   \dfrac{2}{3}x

Perimeter is given by P=2(L+W)

Putting values

\Rightarrow 296=2(x+\dfrac{2}{3}x)\\\\\Rightarrow 296=2(\dfrac{5}{3}x)\\\\\Rightarrow x=\dfrac{296\times 3}{10}=88.8\ m

Length L is 88.8\ m

width W is \frac{2}{3}x=59.2\ m

3 0
3 years ago
Where is the function increasing?
choli [55]

9514 1404 393

Answer:

  A)  1 < x < ∞

Step-by-step explanation:

"Increasing" means the graph goes up to the right. This graph is increasing for values of x greater than 1. (x=1 is a minimum. The graph is decreasing toward the minimum on the left of that value, and increasing from the minimum on the right of that value.)

  1 < x < ∞

4 0
3 years ago
Given right triangle A with a hypotenuse length of 2y + x and a leg length of x + y, and right triangle B with a hypotenuse leng
Zinaida [17]
2y+x=4y+3 (hypotenuse)
x=2y+3 (1st equation)

x+y=x+4 (leg)
y=4 (2nd equation)

plugging 2nd into 1st equation, 
x=11

so x=11, y=4
3 0
3 years ago
PLEASE HELP!!!!
torisob [31]
The answer to the questions

3 0
3 years ago
"what quadrant is...." PLEASE PLEASE HELP!!!! Thank you so so much!!! *will give brainliest*
sdas [7]

Given:

\tan \theta > 0 and \sec \theta.

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only \sin \theta, \text{cosec}\theta are positive and others are negative.

In III quadrant, only \cot \theta, \tan\theta are positive and others are negative.

In IV quadrant, only \cos \theta, \sec\theta are positive and others are negative.

We have,

\tan \theta > 0 and \sec \theta.

Here, \tan \theta is positive and \sec \theta is negative. So, \theta lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

4 0
3 years ago
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