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a_sh-v [17]
3 years ago
7

"what quadrant is...." PLEASE PLEASE HELP!!!! Thank you so so much!!! *will give brainliest*

Mathematics
1 answer:
sdas [7]3 years ago
4 0

Given:

\tan \theta > 0 and \sec \theta.

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only \sin \theta, \text{cosec}\theta are positive and others are negative.

In III quadrant, only \cot \theta, \tan\theta are positive and others are negative.

In IV quadrant, only \cos \theta, \sec\theta are positive and others are negative.

We have,

\tan \theta > 0 and \sec \theta.

Here, \tan \theta is positive and \sec \theta is negative. So, \theta lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

You might be interested in
Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).
saul85 [17]

Answer:

P(x,y) = (0,\frac{11}{5})

Step-by-step explanation:

Given

A = (-2,1)

B = (3,4)

m:n = 2:3

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

Where

(x_1,y_1) = (-2,1)

(x_2,y_2) = (3,4)

m:n = 2:3

This gives:

P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})

P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})

P(x,y) = (\frac{0}{5},\frac{11}{5})

P(x,y) = (0,\frac{11}{5})

5 0
3 years ago
Will give brainliest whats the answer to #11
g100num [7]

The Alpitude is 5 because that is what the positive slope is. The Vertex is (2,6) because that is the lowest point on the graph. The equation is

y=5lx-2l-6 (lx-2l reprsents the absolute value of x-2)

4 0
3 years ago
What is the estimate of 90/7 divided by 1 3/4​
attashe74 [19]

Answer:

7×17/49

Step-by-step explanation:

90/7 × 4/7

90×4 / 7×7

360/49

7 17/49

6 0
3 years ago
^^^^<br> please help :)))
ikadub [295]

2x-1.1/4+x/3=2

2x-1/4+x/3=2

2x-1/4+x/3+1/4=2+1/4

2x+x/3=9/4

3(2x+x/3)=3.94

7x=27/4

7x/7=27/4/7

x=27/8

<h2>PLEASE MARK ME AS BRAINLIEST IF U LIKE MY ANSWER AND SORRY FOR GIVING THE ANSWER LATE BECAUSE I'VE GIVEN U ANSWER FROM MY LAPTOP PLEASE TELL THAT IT'S CORRECT OR NOT</h2>

7 0
3 years ago
Verify that the intermediate value theorem applies to the indicated interval and find the value of c guaranteed by the theorem.
Inessa05 [86]

The intermediate value theorem applies to the indicated interval and the importance of c guaranteed by the theorem is c=2,3.

Especially, he has been credited with proving the following five theorems:  a circle is bisected via any diameter; the bottom angles of an isosceles triangle are the same;  the other (“vertical”) angles are shaped by means of the intersection of two traces are same; two triangles are congruent (of identical form and size.

In mathematics, a theorem is an announcement that has been proved or may be proved. The evidence of a theorem is a logical argument that makes use of the inference guidelines of a deductive system to set up that the concept is a logical result of the axioms and formerly proved theorems.

In line with the Oxford dictionary, the definition of the concept is ''a rule or principle, especially in arithmetic, that may be proved to be true''. For example, in arithmetic, the Pythagorean theorem is a  theorem and is maximum extensively used in the domain of science.

2-1

and interval = [4]

since, function fext is continuous in ginen

interval. And also

+(4) = 42+4

4-1

=

20 = 6667

$(5/4) = ($145/2

stone-1

= 5.833

simle, f(4) > $(5/2), hence Intermediate

Theorem & applies to the indicated

proved.

Now,

= 6

C-1

C-5c +6 = 0

C=2 or c=3

1=

3 or

C= 2, 3

<= 2

Learn  more about theorem here brainly.com/question/26594685

#SPJ4

8 0
2 years ago
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