What is 4x+y=6 written in the quadratic formula

I need help with my quiz what is 100×100

creativ13 [48]

Answer:

10000 (Typo)

Step-by-step explanation:

3 0

2 years ago

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A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi

Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is $\mu \times n$ and the standard deviation is $\sigma\sqrt{n}$

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that $\mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300$

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20000 - 20000}{300}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0

2 years ago

Find the area of the shaded sector.

Vladimir [108]

Given that,

Radius of the circle, r = 8.91 cm

Angle, $\theta=81^{\circ}$

To find,

The area of minor sector.

Solution,

The formula for the area of minor sector is given by the formula as follows :

$A=\dfrac{\theta}{360}\times \pi r^2\\\\A=\dfrac{81}{360}\times \pi \times (8.91)^2\\\\A=56.11\ \text{cm}^2$

So, the area of the shaded sector is $56.11\ \text{cm}^2$ .

8 0

3 years ago

Need help with statistics plssssss

podryga [215]

Answer:

where is the question . ..... we are ready to help you

5 0

2 years ago

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John and Gary share a workload. At a certain point, John worked 2 more hours than Gary. The next day, John has worked 4 of Gary’

il63 [147K]

If these both men were working at normal hours, and then, (John) worked "2 more hours" than Gary has, this would just mean that he has worked more.

x+2= x+2.

Now if John has worked the double amount, 4 more times than Gary's usual hours, this would mean something quite different.

Then the expression would look like, (x+2×4x)

We don't know how many hours are the "usual hours", this is what "x" would then represent.

John has then worked (4×2+x) more hours than Gary.

Your answer: (4×2+x)

4 0

2 years ago