All categories

2 years ago

I could use any help as soon as possible in need this due tomorrow for exams

Mathematics

2 answers:

EastWind [94]2 years ago

6 0

The answer woukd be 23

nexus9112 [7]2 years ago

5 0

GCF for 27 and 14 is none

You might be interested in

Type the correct answer in the box. x y 3 10 20 In the table, the relation (x, y) is not a function if the missing value of x is

yan [13]

The relation is not a function if any x-value is repeated.

Assuming you have

(x, y) = (3, 10), (__, 20)

if x = 3, the relation is not a function.

3 0

3 years ago

Read 2 more answers

Help please bed asap thank you!!!

Mkey [24]

Answer:

Step-by-step explanation:

8 0

1 year ago

) Asuka travels at an average speed of 50 mph for 20 miles.

Anuta_ua [19.1K]

Answer: 41.86 miles/hour

Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [in brackets].

MPH MILES HOURS

50 20 [0.4]

[40] 70 1.75

Totals 90 miles 2.15 hours

Average = 90 miles/2.15 hours

41.86 mph

5 0

2 years ago

Broooo plzzz helpppp

Sindrei [870]

Answer:

3 3/5 + 1 1/4 = 4 17/20

7/8 + 1/12 = 23/24

8/9 - 2/5 = 22/45

5 1/4 - 2 2/3 = 2 7/12

Step-by-step explanation:

3 3/5 + 1 1/4

First convert into improper fractions

= 18/5 + 5/4

Now find the common denominator

72/20 + 25/20 =

97/20

Now simplify

4 17/20

Next problem:

7/8 + 1/12

find the common denominator

21/24 + 2/24 =

23/24

Next problem:

8/9 - 2/5

find the common denominator

40/45 - 18/45 =

22/45

Next problem:

5 1/4 - 2 2/3

First convert into improper fractions

21/4 - 8/3

find the common denominator

63/12 - 32/12 =

31/12

Now simplify

2 7/12

5 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers