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GuDViN [60]
3 years ago
9

I could use any help as soon as possible in need this due tomorrow for exams

Mathematics
2 answers:
EastWind [94]3 years ago
6 0
The answer woukd be 23
nexus9112 [7]3 years ago
5 0
GCF for 27 and 14 is none
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Determine the truth value of the conjecture. If it is false, provide a counterexample. Conjecture: All squares are rectangles.
PolarNik [594]
It is true.

Rectangle is a parallelogram with 4 right angles, so as a square.
4 0
3 years ago
The total cost (in dollars) for a company to manufacture and sell x items per week is C=40x+180, whereas the revenue brought in
crimeas [40]

Answer:

The company needs to sell either 30 or 40 items.

Step-by-step explanation:

We are given that the cost for selling <em>x</em> items given by the function:

C(x)=40x+180

And the revenue for selling <em>x</em> items is given by:

R(x)=68x-0.4x^2

The profit function is the cost function subtracted from the revenue function:

P(x)=R(x)-C(x)

Substitute and simplify:

\displaystyle \begin{aligned} P(x)&=(68x-0.4x^2)-(40x+180)\\&=68x-0.4x^2-40x-180\\&=-0.4x^2+28x-180\end{aligned}

To find how many items must be sold in order to obtain a weekly profit of $300, we can let <em>P</em> equal 300 and solve for <em>x</em>. So:

300=-0.4x^2+28x-180

Solve for <em>x</em>. Subtract 300 from both sides:

-0.4x^2+28x-480=0

We can divide both sides by -0.4:

x^2-70x+1200=0

Factor:

(x-40)(x-30)=0

Zero Product Property:

x-40=0\text{ or } x-30=0

Solve for each case:

x=40\text{ or } x=30

So, in order to obtain a weekly profit of $300, the company need to sell either 30 <em>or</em> 40 items.

7 0
3 years ago
Which are solutions to 3sin^2 θ - 2sin θ = 0, 90°≤θ≤90°
jeka57 [31]

Answer:

The solutions of the equation are -41.8° , 0.0° , 41.8°

Step-by-step explanation:

∵ 3 sin²Ф - 2 sinФ = 0 is a quadratic function

∵ The domain of the function is -90° ≤ Ф ≤ 90°

- Lets take sinФ as a common factor

∴ sinФ (3 sinФ - 2) = 0

- Two terms multiplied by each other = 0

∴ One of them must be equal zero

∴ sinФ = 0 or 3 sinФ - 2 = 0

- If sinФ = 0 ⇒ Ф = 0.0°

- If 3 sinФ - 2 = 0 ⇒ 3 sinФ = 2 ⇒ sin Ф = 2/3

∵ sinФ 2/3

∴ Ф = 41.8° ⇒ Ф ≤ 90° (in first quadrant)

∵ -90° ≤ Ф ≤ 90°

∴ Ф = -41.8° ⇒ Ф ≥ -90° (in fourth quadrant)

∴ The solutions of the equation are -41.8° , 0.0° , 41.8°

4 0
4 years ago
3/8 multiplied by 4/11
nlexa [21]
The answer is .36363636363
7 0
4 years ago
Read 2 more answers
Do the following set of points describe a function, a relation, both or neither?
harkovskaia [24]

Answer:

It's Both

Step-by-step explanation:

for the first two co-ordinates, there are many y-value for a single x-value, then for the last two co-ordinates theres a single y-value for one x-value

4 0
3 years ago
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