Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
20: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200
14: 14, 28, 42, 56, 70, 84, 98, 112, 126, 140
140 is the smallest number they have in common.
Answer:
g(-3) = 23
Step-by-step explanation:
This question is telling us that x = -3. Knowing this, we can plug x into the equation and solve to find g(-3).

Square -3 to get 9
Multiply 9 by 3 to get 27
Subtract 4 from 27 to get 23
Thus, g(-3) is equal to 23.
I hope this helps! Good luck!
Answer:135.2
Step-by-step explanation: