Answer:
7.211
Step-by-step explanation:
-For two points in the complex plane, the distance between the points is the modulus of the of the difference of the two complex numbers.
-Point 2-4i has the coordinates (2,-4)
-Point 6+i has the coordinates (6,1)
#We must find the distance between the two coordinates (2,-4) and (6,1):

Hence, the distance between the two points is 7.211
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
X/8 - 10 = x/3
bring the values with the variable on one side
x/3 - x/8 = 10
find a common denominator and subtract these fractions
8x/24 - 3x/24 = -10
now subtract fractions
8x - 3x = 5x
5x/24 = -10
multiply both sides by 24
5x = -240
divide both sides by 5
x = -48
the number is -48
Distance=speed x time
so it would be 28 x 6=168