<h2>
Answer:</h2>
The probability that exactly one customer dines on the first floor is:
0.26337
<h2>
Step-by-step explanation:</h2>
We need to use the binomial theorem to find the probability.
The probability of k success in n experiments is given by:
where p is the probability of success.
Here p=1/3
( It represents the probability of choosing first floor)
k=1 ( since only one customer has to chose first floor)
n=6 since there are a total of 6 customers.
This means that:
Answer:
9.6 square inches.
Step-by-step explanation:
We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.
First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:
Solve for the scale factor <em>k: </em>
<em />
<em />
<em />
Recall that to scale areas, we square the scale factor.
In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.
Hence, the area of ΔEDF is:
In conclusion, the area of ΔEDF is 9.6 square inches.
Answer:
B.) y=csc x
Step-by-step explanation:
The cosecant function has a minimum magnitude of 1, so its range excludes any values in the range -1 < y < 1.
y = csc(x) . . . has a range that does not include -0.8
Answer:
The correct option is;
Low
Step-by-step explanation:
Given that the P-value of the linear correlation = 0.001, we have that the P-value is a demonstration that a linear correlation that has a value in the range of the given correlation is ,most arguably very low
From the z-table, a P-value of 0.001 corresponds to a z-value of -3.09, we have that in a normal distribution since 95% of the scores have a z-score of between -2 and 2, the z-score of -3.09 is very distant from the mean and having a low value, whereby the P-value shows that the likelihood of finding another linear correlation that is as far from the mean as the given correlation is very low.
