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3 years ago

Help will give branliest 15 pointss

Mathematics

2 answers:

siniylev [52]3 years ago

3 0

Answer:

2x+2

Step-by-step explanation:

the green brick is x, and the yellow squares mean 1.

add them all together and you get 2x(two big green ones) + 2(two yellow ones)

nordsb [41]3 years ago

3 0

Answer:

2x+2

Step-by-step explanation:

If each yellow block represents one, then having two of them equals 2.

Same with the green blocks, x+x = 2x.

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For what values of x is the expression below defined?<br> √x+4÷√1-x

wariber [46]

Answer:

x=1

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

4 years ago

Is 5+ 3 and 5-3 related facts explain

ololo11 [35]

Well maybe because the only thing that is different is the - and +

3 0

3 years ago

(-5,-1); 2y=2x-4 help me ASAP please

PIT_PIT [208]

Answer:

u trrahs at fritnote

Step-by-step explanation:

6 0

3 years ago

One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.

seraphim [82]

Answer: The numbers are: " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x ;

y = 84 + x ;
___________________________________________________
So, we have:

x = (1/5) y ;

and: y = 84 + x ;

Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;

y = 84 + [ (1/5)y ]

Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ] ;

to get:

[ (4/5)y ] = 84 ;

       ↔    (4y) / 5 = 84 ;

        → 4y = 5 * 84 ;

      Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y = 5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
x = (1/5) y ;

OR:

y = 84 + x ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y

    → (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;

___________________________________________________
So, x = 21; y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?

105 = ? 105 ? Yes!
___________________________________________________
The numbers are: " 21 " and "105 " .
___________________________________________________

6 0

3 years ago