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qwelly [4]
3 years ago
11

Solve the equation: x2 = 1

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0
2x=1

You must divide both sides by 2 to get rid of the 2 the left side.

2/2x=1/2

x=1/2

there is only one solution.
oee [108]3 years ago
3 0

Answer:

x = 0.5

Step-by-step explanation:

hope this helps!

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Which graph shows the image of the triangle reflected across the line of reflection shown?
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Answer:

D .points (2,2) (4,4) (0,9)

Step-by-step explanation:

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2 years ago
This is the same question as last time just not blurry.
AveGali [126]
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8 0
3 years ago
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Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]

It's hard to tell where one set ends and the next starts.  I think it's

A. 25, 36, 44, 51, 62, 77

B. 3, 3, 3, 7, 9, 9, 10, 14

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.

A. 25, 36, 44, 51, 62, 77

That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.

B. 3, 3, 3, 7, 9, 9, 10, 14

Average around 7, sigma around 4, within 2 sigma, seems ok.

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

Average around 20, sigma around 8, that 39 is hanging out there past two sigma.  Let's reserve judgement and compare to the next one.


D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82

Average around 74, sigma 8, seems very tight.

I guess we conclude C has the outlier 39.  That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.  



3 0
3 years ago
Read 2 more answers
Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem
Verizon [17]

Answer:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

\frac{dT}{dt} = -k(T-T_0) \\

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

3 0
3 years ago
Match each point label on the box it to its description.
Ahat [919]
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4 0
2 years ago
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