All categories

2 years ago

What is the smallest number greater than 1 that leaves a remainder 1 when divided by each of 2, 3, and 4?

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

6 0

Answer:

YOOOO I LOVE YOUR PROFILE PICTURE. SILENT VOICE IS SO SAD BUT SO GOOD <3 :D

You might be interested in

Help please!!

zvonat [6]

(a/b) / (c/d) = (a/b)*(d/c) that is the rule so:

(3/4)/(3/16) is equal to:

(3/4)*(16/3) which is equal to

16/4

4

4 0

2 years ago

Read 2 more answers

A small theater sold 72 tickets for a play. The ratio of adult tickets to child tickets was 4:1. The ratio of adult tickets to s

Y_Kistochka [10]

Answer:

Adult 36

Children 9

senior 27

Step-by-step explanation:

We have 3 types of tickets as seen from the question;

Adult, children and seniors tickets.

Now, looking at the question critically,

Since the ratio of adults to children and senior citizens stands at 4: a specific value, we can then conclude that the ratio of tickets sold is 4:1:3

where 1 and 3 represents the ratio for the children and seniors respectively

So let’s calculate the individual ratio now.

For the total, we have 4 + 1 + 3 = 8

Thus, for the adults, we have 4/8 * 72 = 36

For the children, we have 1/8 * 72 = 9

For the seniors, we have 3/8 * 72 = 27

3 0

3 years ago

35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa

Tatiana [17]

Answer:

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

$\bar X=1450$ represent the sample mean for the SAT scores

$\mu$ population mean (variable of interest)

$s^2 = 900$ represent the sample variance given

n=25 represent the sample size

Solution

The confidence interval for the true mean is given by :

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The sample deviation would be $s=\sqrt{900}= 30$

The degrees of freedom are given by:

$df=n-1=2-25=24$

The Confidence is 0.954 or 95.4%, the value of $\alpha=0.046$ and $\alpha/2 =0.023$ , assuming that we can use the normal distribution in order to find the quantile the critical value would be $z_{\alpha/2} \approx 2.0$

The confidence interval would be

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

3 0

3 years ago

Can someone explain how to solve this and the solution? Please and thank you :)

Verizon [17]

25 > 2x + 8 - 66

first simplify all numbers

25 > 2x + (8 - 66)
25 > 2x - 58

Then add 58 to both sides

25 (+58) > 2x - 58 (+58)
83 > 2x

Finally divide 2 from both sides to isolate the x

83/2 > 2x/2

41.5 > x

hope this helps

3 0

2 years ago

Please help fast its quiz. :(

dezoksy [38]

Answer:

What is the question??

Thank you for the points

8 0

2 years ago

Read 2 more answers