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Thepotemich [5.8K]
3 years ago
10

Find the area of the figure. (Sides meet at right angles.)

Mathematics
1 answer:
DedPeter [7]3 years ago
7 0

9514 1404 393

Answer:

  40 square feet

Step-by-step explanation:

The sum of horizontal lengths is 2+4+2 = 8 ft, so the bottom rectangular portion of the figure has an area of ...

  A = bh = (8 ft)(3 ft) = 24 ft²

The top rectangular portion of the figure has an area of ...

  A = bh = (4 ft)(4 ft) = 16 ft²

Then the total area of the figure is ...

  24 ft² +16 ft² = 40 ft² . . . . area of the figure

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Answer:

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Using the Determinant method to find the roots of this equation

x=\frac{-1\pm \sqrt{1^2-4*2*(-4)}}{2\times 2}\\\\ x=\frac{-1 \pm \sqrt{32}}{4}{\text{Using the formula}}x=\frac{-b\pm\sqrt{D}}{2a}, {\text{where}},D=b^2-4 ac

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

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So, there is no solution.

You can solve these two equation graphically also.

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