Answer:
C. 20 cm^3
Step-by-step explanation:
Using the equation D=m/v, you would plug in the given mass (227 g) into m and the given density of lead (11.35 g/cm^3). Solving for v=m/D, we find the answer to be 20 cm^3.
Also, you could cancel out all the answers except C because it is the only one in units of volume (1 cm^3 = 1 mL).
The answer is 14 you simplify the fraction 75/100 to 3/4 and multiply by 56 4 divides 56 into 14 multiply this by 3 and subtract from 56, 56-42=14 books
Answer:
N=7
Step-by-step explanation:
1. Distribute the 6 into the parentheses
6+30n-6n=174
2.combine like terms
6+24n=174
3. Subtract 6 on both sides
24n=168
4.now divide
24/24 cancels out 24/168 is what 7 soooo
n=7
Answer:
![A=600\: u^{2}](https://tex.z-dn.net/?f=A%3D600%5C%3A%20u%5E%7B2%7D)
<u>The correct answer is letter c.</u>
Step-by-step explanation:
The area equation of a triangle is given by:
(1)
Where:
b is the base
h is the height
Let's find first the angle MJK (α), using the tangent definition.
![tan(\alpha)=\frac{24}{32}](https://tex.z-dn.net/?f=tan%28%5Calpha%29%3D%5Cfrac%7B24%7D%7B32%7D)
![\alpha=tan^{-1}(\frac{24}{32})](https://tex.z-dn.net/?f=%5Calpha%3Dtan%5E%7B-1%7D%28%5Cfrac%7B24%7D%7B32%7D%29)
![\alpha=36.9^{\circ}](https://tex.z-dn.net/?f=%5Calpha%3D36.9%5E%7B%5Ccirc%7D)
Now, if α = 37° then β (angle JLK) must be:
![37^{\circ} + \beta + 90^{\circ}=180^{\circ}](https://tex.z-dn.net/?f=37%5E%7B%5Ccirc%7D%20%2B%20%5Cbeta%20%2B%2090%5E%7B%5Ccirc%7D%3D180%5E%7B%5Ccirc%7D)
![\beta=53^{\circ}](https://tex.z-dn.net/?f=%5Cbeta%3D53%5E%7B%5Ccirc%7D)
Now, we can find the distance ML using again the tangent definition:
![tan(\beta)=\frac{24}{ML}](https://tex.z-dn.net/?f=tan%28%5Cbeta%29%3D%5Cfrac%7B24%7D%7BML%7D)
![ML=\frac{24}{tan(53)}](https://tex.z-dn.net/?f=ML%3D%5Cfrac%7B24%7D%7Btan%2853%29%7D)
![ML=18](https://tex.z-dn.net/?f=ML%3D18)
The base of the triangle LKJ will be:
![b=32+ML=32+18=50](https://tex.z-dn.net/?f=b%3D32%2BML%3D32%2B18%3D50)
Therefore, using equation (1) the area of △LKJ will be:
![A=\frac{50*24}{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B50%2A24%7D%7B2%7D)
![A=600\: u^{2}](https://tex.z-dn.net/?f=A%3D600%5C%3A%20u%5E%7B2%7D)
The correct answer is c.
I hope it helps you!