it is impossible
Step-by-step explanation:
a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d,
and e are not zero
PROVE
a/b * b/c * c/d * d/e
= (a/b *b/c) * (c/d * d/e)
= ab/bc * (c/d * d/e)
= a/c * (c/d * d/e)
= a/c * (cd/de)
= a/c * c/e
= ac/ce
= a/e
Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that
b, c, d, and e are not zero
The first thing you want to do is plug in x and y into both equations:
a(3) + b(4) = 4
b(3) + a(4) = 8
rearrange to line up a’s and b’s
3a + 4b = 4
4a + 3b = 8
now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.
4(3a + 4b = 4) = 12a + 16b = 16
3(4a + 3b = 8) = 12a + 9b = 24
Now we subtract the bottom equation from the top and solve for b:
12a + 16b - (12a + 9b) = 16 - 24
7b = -8
b = -8/7
Now we plug back in for b to one of the original equations:
3a + 4(-8/7) = 4
3a + (-32/7) = 4
3a - (32/7) = 4
3a = 4 + (32/7)
3a = (28/7) + (32/7)
3a = 60/7
a = (60/7)/3 = 20/7.
Finally, plug a and b in together to double check using the second equation.
4a + 3b = 8
4(20/7) + 3(-8/7) = ?
(80/7) - (24/7) = ?
56/7 = 8.
Let
be the time it takes for pumps A, B, and C (respectively) to fill 1 tank. Then

Now,

Then

This means

and

Working together, all 3 pumps would operate at a rate of

or 1 tank in 1 hour, so the answer is D.
Hello,
mean=1/2*(1+88)*88/88=89/2=44.5
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