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2 years ago

Pls help me get this right..

Mathematics

2 answers:

jekas [21]2 years ago

7 0

Answer:

Step-by-step explanation:

Subtract the 3x to the other side then divide by 2 which gives you -3/2 not -2/3

charle [14.2K]2 years ago

6 0

3x+2y=4 or option c is the correct answer:)

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A certain company's main source of income is selling cloth bracelets. The company's annual profit (in thousands of dollars) as a

tester [92]

Answer:

8 thousand dollars

Step-by-step explanation:

The company's annual profit (in thousands of dollars) as a function of the price of a bracelet (in dollars) is modeled by: P(x)=-2x^2+16x-24

To find maximum profit , we need to find out the vertex

x coordinate of vertex formula is -b/2a

$P(x)=-2x^2+16x-24$

a=-2 and b = 16

$x= \frac{-b}{2a}= \frac{-16}{2(-2)} = 4$

Now we plug in 4 for x and find out P(4)

$P(x)=-2(4)^2+16(4)-24$ = 8

So the maximum profit the company can earn is 8 thousand dollars when price = $4

6 0

3 years ago

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Name the consecutive (same side) exterior angles and interior angles

konstantin123 [22]

Answer:

Consecutive Interior Angles

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∠6+∠13= 180

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Consecutive Exterior Angles

Consecutive exterior angles also equal 180 degrees, but they are on the outside of the parallel lines. They are...

∠1+∠10= 180

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3 0

2 years ago

6x(0,5x+3)+3x(1-x)-(1-10x)=7

Eddi Din [679]

Answer:

answer is 

Step-by-step explanation:

ok ok ok ok ok ok ok ok ok ok ok ok

7 0

3 years ago

ASAPPPP HELPPPP PLEASEEEE

nataly862011 [7]

Answer:

27.6

Step-by-step explanation:

sin29=x/57

0.48480962=x/57

x≈27.6

4 0

2 years ago

What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1

Ratling [72]

Answer:

$\sqrt3$

Step-by-step explanation:

To find:

The value of $tan60^\circ$ = ?

Solution:

Kindly consider the equilateral $\triangle ABC$ as attached in the answer area.

Let the side of triangle = $a$ units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = $\frac{a}{2}$

Using Pythagorean Theorem in $\triangle ABD$ :

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

Side AD = $\frac{\sqrt3}{2}a$

Using Trigonometric ratio:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tanB = \dfrac{AD}{BD}$

Putting the values of AD and BD:

$tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}$

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2 years ago

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