Answer:
The flocculation basin often has a number of compartments with decreasing mixing speeds as the water advances through the basin. ... This compartmentalized chamber allows increasingly larger floes to form without being broken apart by the mixing blades.
Answer:
CO2
Explanation:
- There are two types of molecules
- Polar
- Non polar
Non polar molecules are insoluble in water .
Answer:
is the value of the rate constant.
Explanation:
Let the order of the reaction be x.
The rate law of the reaction can be written as:
![R=k[H_2O_2]^x](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5Ex)
1. Rate of the reaction when concentration changes from 0.882 M to 0.697 M in 0 seconds to 60 seconds.
![0.00308 M/s=k[0.697 M]^x](https://tex.z-dn.net/?f=0.00308%20M%2Fs%3Dk%5B0.697%20M%5D%5Ex)
..[1]
2. Rate of the reaction when concentration changes from 0.697 M to 0.566 M in 240 seconds to 360 seconds.
![0.00218 M/s=k[0.236 M]^x](https://tex.z-dn.net/?f=0.00218%20M%2Fs%3Dk%5B0.236%20M%5D%5Ex)
..[2]
[1] ÷ [2]
![\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}](https://tex.z-dn.net/?f=%5Cfrac%7B0.00308%20M%2Fs%7D%7B0.00227%20M%2Fs%7D%3D%5Cfrac%7Bk%5B0.697%20M%5D%5Ex%7D%7Bk%5B0.236M%5D%5Ex%7D)
Solving fro x:
x = 0.92 ≈ 1
![R=k[H_2O_2]^1](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5E1)
![0.00308 M/s=k[0.697 M]^1](https://tex.z-dn.net/?f=0.00308%20M%2Fs%3Dk%5B0.697%20M%5D%5E1)
![k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.00308%20M%2Fs%7D%7B%5B0.697%20M%5D%5E1%7D%3D0.00442%20s%5E%7B-1%7D)
is the value of the rate constant.
Answer: The charge on a sulfide ion is –2.
Explanation:
Molarity= (number of moles of that substance) / (Volume of solution in litres)
7= (number of moles of HCl) / 0.05
Thus,
Number of moles of HCl = 7 x 0.05 = 0.35
The number of moles of HCl will remain unchanged.
Now, for new solution,
0.35= 0.35 / (New volume of solution in litres)
Thus,
New volume = 1 litre
Thus, amount of water added = 1- 0.05 litre = 5.0 M
