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LenaWriter [7]
2 years ago
8

How might the yield of 1-bromobutane be affected if water was not added, and what product(s) would be favored?

Chemistry
1 answer:
jek_recluse [69]2 years ago
5 0
  • Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.
  • Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.
  • If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.
<h3>What is Bromination?</h3>
  • When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.
  • After bromination, the result will have different properties from the initial reactant.
  • For example, an alkene is brominated by electrophilic addition of Br_{2}.
  • Benzene ring bromination by electrophilic aromatic substitution.

Learn more about Bromine here:

brainly.com/question/862562

#SPJ4

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You have a cup of tea (250 ml) that is 375 K which is too hot to drink. It needs to be cooled to 350 K before you can drink it.
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Answer:

The hot tea should transfer <em>25.63 kJ</em> the surroundings to cool the tea.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).

m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.

c is the specific heat of the hot tea (c = 4.10 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).

<em>∴ Q = m.c.ΔT</em> = (250 g)(4.10 J/°C.g)(-25°C)) = <em>- 25630 J = - 25.63 kJ.</em>

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