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LenaWriter [7]
2 years ago
8

How might the yield of 1-bromobutane be affected if water was not added, and what product(s) would be favored?

Chemistry
1 answer:
jek_recluse [69]2 years ago
5 0
  • Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.
  • Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.
  • If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.
<h3>What is Bromination?</h3>
  • When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.
  • After bromination, the result will have different properties from the initial reactant.
  • For example, an alkene is brominated by electrophilic addition of Br_{2}.
  • Benzene ring bromination by electrophilic aromatic substitution.

Learn more about Bromine here:

brainly.com/question/862562

#SPJ4

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What happens in a condensation reaction?
Agata [3.3K]

A) Head to tail joining of monomers. :) (confirmed correct answer, I took the test)

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3 years ago
A compound is found to contain 47 percent potassium 14.5 percent carbon and 38.5 percent oxygen by the way the molar mass of the
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3 years ago
A sample of neon initially has a volume of 2.80 L at 23 degrees Celsius. What is final temperature, in degrees Celsius, is neede
finlep [7]

The relation between the volume and the temperature of the gas is given by Charles's law. The final temperature of the gas at 0.75 liters is -193.8°C.

<h3>What is Charles's law?</h3>

Charles's law was derived from the ideal gas equation and is used to state the relationship between the temperature and the volume of the gas. With a decrease in volume the temperature decreases.

If the pressure is kept constant then with an increase in temperature the volume of the gas expands. The law is given as,

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

Initial volume (V₁) = 2.80 L

Initial temperature (T₁) = 23 °C = 296.15 K

Final volume (V₂) = 0.75 L

Final temperature = T₂

Substituting the values above as:

T₂ = (V₂ × T₁) ÷ V₁

= 0.75 × 296.15 ÷ 2.80

= 79.325 K

Kelvin is converted as, 79.325K − 273.15 = -193.8°C

Therefore, the final temperature is -193.8°C.

Learn more about Charle's law, here:

brainly.com/question/16927784

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7 0
1 year ago
What is the specific heat of iron, if it requires 1120 J of heat energy to raise the
IRISSAK [1]

Answer:

Specific heat is defined as the amount of heat needed to raise the temperature by one degree celsius. Therefore, in 1 kg there are 100 grams so, 10 grams equal 0.01 Kg. Thus, calculate the specific heat value as follows. Thus, we can conclude that specific heat of the given metal is 0.5 .

Explanation:

4 0
3 years ago
Um...id.k how to do chemistry...help please?
qaws [65]

Answer:

NaBr

Explanation:

3 0
3 years ago
Read 2 more answers
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