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1 year ago

How might the yield of 1-bromobutane be affected if water was not added, and what product(s) would be favored?

Chemistry

1 answer:

jek_recluse [69]1 year ago

5 0

Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.

Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.

If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.

<h3>What is Bromination?</h3>

When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.

After bromination, the result will have different properties from the initial reactant.
For example, an alkene is brominated by electrophilic addition of $Br_{2}$ .
Benzene ring bromination by electrophilic aromatic substitution.

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One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) techniq

frozen [14]

Answer:

a. i. 8.447 × 10⁻³ T ii. 27.14 cm

b. i. 2.14 cm ii. It is easily detectable.

Explanation:

i. What strength of magnetic field is required?

Since the magnetic force F = Bqv equals the centripetal force F' = mv²/r on the C12 charge, we have

F = F'

Bqv = mv²/r

B = mv/re where B = strength of magnetic field, m = mass of C12 isotope = 1.99 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q = charge on C 12 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron)and r = radius of semicircle = 25.0 cm/2 = 12.5 cm = 12.5 × 10⁻² m

So,

B = mv/rq

B = 1.99 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (12.5 × 10⁻² m × 1.602 × 10⁻¹⁹ C)

B = 16.915 × 10⁻²³ kgm/s ÷ (20.025 × 10⁻²¹ mC)

B = 0.8447 × 10⁻² kg/sC)

B = 8.447 × 10⁻³ T

(ii) What is the diameter of the 13C semicircle?

Since the magnetic force F = Bq'v equals the centripetal force F' = mv²/r' on the C13 charge, we have

F = F'

Bq'v = mv²/r'

r' = mv/Be where r = radius of semicircle, B = strength of magnetic field = 8.447 × 10⁻³ T, m = mass of C12 isotope = 2.16 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q' = charge on C 13 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron) and = d/2 = 12.5 cm = 12.5 × 10⁻² m

So, r' = mv/Be

r' = 2.16 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (8.447 × 10⁻³ T × 1.602 × 10⁻¹⁹ C)

r' = 18.36 × 10⁻²³ kgm/s ÷ 13.5321 × 10⁻²² TC)

r' = 1.357 × 10⁻¹ kgm/TC)

r' = 0.1357 m

r' = 13.57 cm

Since diameter d' = 2r', d' = 2(13.57 cm) = 27.14 cm

i. What is the separation of the C12 and C13 ions at the detector at the end of the semicircle?

Since the diameter of the C12 isotope is 25.0 cm and that of the C 13 isotope is 27.14 cm, their separation at the end of the semicircle is 27.14 cm - 25.0 cm = 2.14 cm

ii. Is this distance large enough to be easily observed?

This distance of 2.14 cm easily detectable since it is in the centimeter range.

7 0

2 years ago

Acid indigestion is sometimes neutralized with an antacid such as magnesium hydroxide (Mg(OH)2). What products will be released

Lunna [17]

Answer: d) $MgCl_2$ and $H_2O$ 

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

A neutralization reaction is a double displacement reaction in which an acid reacts with base to produce salt and water. The $H^+$ ions from water reacts with $OH^-$ ions from base to give water.

$2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O$

Thus products that will be released when the antacid is mixed with the hydrochloric acid in the stomach are $MgCl_2$ and $H_2O$ 

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3 years ago

Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed.

ddd [48]

Based on the incomplete neutralization reaction above, the corresponding salts that each reaction would form are as follows:
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2. 2NaOH + H2CO3 ----Na2CO3 with water as a byproduct
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2 years ago

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The energy and state changes that occur when freezing rain falls and solidfies on a wire fence

Alex787 [66]

Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.

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2 years ago

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4. Synthesis problems. Propose a synthetic route from the starting material to the product. In your answer, show each individual

Troyanec [42]

The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.

Describe reagents.

A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.

With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.

In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.

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1 year ago