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2 years ago

Determine whether a triangle with the given vertices is a right triangle.

Mathematics

1 answer:

____ [38]2 years ago

7 0

The answers are:

A) right triangle
B) right triangle
C) right triangle

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What is the diameter of a circle with a radius of 7 inches

In-s [12.5K]

Answer:

Step-by-step explanation:

the diameter is the radius multiplied by 2

7 0

3 years ago

Toniac 123 can you please help me with these questions. They are part of of the question you answered. There is another question

uranmaximum [27]

5/12+5/12=10/12
10/12+10/12=20/12 wich =1.666666666666667theres ur answer to one.
dont know the answer to the other one
Sorry
Hope that helps

8 0

3 years ago

The volume of a cubical box is 474.552m3.Find the length of each side of the box

Cerrena [4.2K]

The formula of a volume of a cube:

$V=a^3$

We have $V=474.552\ m^3$

Substitute:

$a^3=474.552\to a=\sqrt[3]{474.552}\\\\a=7.8\ m$

Answer: The length of each side of the box is equal 7.8 m.

8 0

3 years ago

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

4^3 > 6^2 Is this right or not right if not what other sign needs to go there.

Bess [88]

Answer:

that is right

Step-by-step explanation:

because 4×4×4 equals 64 and 6×6 equals 37 so it is 4^3>6^2

6 0

2 years ago

Read 2 more answers