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lawyer [7]
1 year ago
5

Please Help I don’t get this!!!☹️☹️Im gonna have a meltdown!

Mathematics
1 answer:
marta [7]1 year ago
7 0

Answer:

Y = -5X

Step-by-step explanation:

<u>Don't</u><u> </u><u>have</u><u> </u><u>a</u><u> </u><u>meltdown</u><u>.</u><u> </u><u>It's</u><u> </u><u>not</u><u> </u><u>good</u><u> </u><u>for</u><u> </u><u>you</u><u>. </u><u>Glad</u><u> </u><u>to</u><u> </u><u>help</u><u> </u><u>you</u><u> </u><u>out</u><u>.</u> :)

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VERY EASY 7TH GRADE QUESTION FIRST ANSWER IS BRAINLIEST
nadezda [96]

Answer:

A. \:  \boxed{ 5c - 5 = 45 }

Step-by-step explanation:

let \: the \: cost \: of \: thier \: meal \: be \:  \to \: c \\ then \to \\ the \: five \: of \: them \: will \: cost \: 5c \\ assuming \: he \: also \: ordered : it \: would \: had \: \\  been \: 5c = 45 \\   \boxed{but \: no}\\ since \: he \: did \: not \: oder \: but \: eat \: the \: rest \: \\  of \: the \: meal \to \\ the \: equation \: is \: givn \: by \to \\ \boxed{ 5c - 5 = 45}

4 0
2 years ago
Help me with my work if not finested my mom will beat me
Aliun [14]

Answer:

B

Step-by-step explanation:

x - 3 = y

7 0
2 years ago
The nine squares of a 3-by-3 chessboard are to be colored red and blue. The chessboard is free to rotate but cannot be flipped o
nignag [31]

Answer:

a_n = 2^{\frac{n^2-1}{4} + 1} + \frac{2^{n^2} - \, 2^{\frac{n^2-1}{4} + 1}}{4}

For n = 3, there are 134 possibilities

Step-by-step explanation:

First, lets calculate the generating function.

For each square we have 2 possibilities: red and blue. The Possibilities between n² squares multiply one with each other, giving you a total of 2^n² possibilities to fill the chessboard with the colors blue or red.

However, rotations are to be considered, then we should divide the result by 4, because there are 4 ways to flip the chessboard (including not moving it), that means that each configuration is equivalent to three other ones, so we are counting each configuration 4 times, with the exception of configurations that doesnt change with rotations.

A chessboard that doesnt change with rotations should have, in each position different from the center, the same colors than the other three positions it could be rotated into. As a result, we can define a <em>symmetric by rotations chessboard</em> with only (n²-1)/4 + 1 squares (the quarter part of the total of squares excluding the center plus the center).

We cocnlude that the total of configurations of symmetrical boards is 2^{\frac{n^2-1}{4} + 1}

Since we have to divide by 4 the rest of configurations (because we are counted 4 times each one considering rotations), then the total number of configutations is

a_n = 2^{\frac{n^2-1}{4} + 1} + \frac{2^{n^2} - \, 2^{\frac{n^2-1}{4} + 1}}{4}

If n = 3, then the total amount of possibilities are

a_3 = 2^{\frac{3^2-1}{4} + 1} + \frac{2^{3^2} - \, 2^{\frac{3^2-1}{4} + 1}}{4} =  134

3 0
3 years ago
Some help me please and thank you
lisov135 [29]

Answer:

6/15 + 5/15 = 11/15

Step-by-step explanation:

cross multiply the numbers to get a common denominators, then add

5 0
2 years ago
I need This ASAP you need to solve for h
wariber [46]

Answer:

(S-2~r^2)/2~r=h

Step-by-step explanation:

I subtract -2~r^2 on both sides

S-2~r^2=2~rh

Then I divide both by 2~r

(S-2~r^2)/2~r=h

7 0
3 years ago
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