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monitta
2 years ago
7

Convert 1101 base 2 to base 10

Mathematics
1 answer:
Svetllana [295]2 years ago
6 0

Use the Internet to find an article that presents a forecast of the economy's performance in the next three months to a year. Once you have found and read your article, record your summary using the following format in the box below and include the link. Be sure to include the URL links you used as resources in the space below.

Im Pewdiepied

Paragraph #1 - Summary of article including the link.

Paragraph #2 - How it relates to entrepreneurship.

Paragraph #3 - Your opinion of whether or not you agree with the prediction and the evidence provided to support the forecast.

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What is 7 7/8 dvided by 3 1/8 mixed numbers
zhannawk [14.2K]

Answer:

2.52

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The slope of the lines that passes through the points (-10,0) and (-13,3)
goldenfox [79]

Answer:

-1

Step-by-step explanation:

The formula to find the slope of a line is:

\frac{y_{2}- y_{1} }{x_{2} -x_{1} }

where (x1, y1) and (x2, y2) are points on the line. We can substitute the points (-10, 0) and (-13, 3) into the formula and simplify:

\frac{3-0}{-13-(-10)} =\frac{3}{-13+10} =\frac{3}{-3} =-1

This means the slope of the line is -1.

4 0
2 years ago
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod
tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1                2              3

495      525            470

500         515           480

505        505            460

<u>500         515             470        </u>

<u>∑2000     2060         1880</u>

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4=  470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using  μ ± σ , μ±2 σ  or μ ± 3 σ.

In this question the limits are determined by using  μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4=  470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other  two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0
2 years ago
Tom knows that in his school 10 out of every 80 students are left-handed. There are 384 students in toms school. How many studen
Vika [28.1K]
Answer:

C (48)

explanation:

firstly, divide 384 by 80. This gives you 4.8. So, since 10 out of every 80 students are left handed we have to times 4.8 by 10 which gives you 48.
4 0
3 years ago
Points A, B, and C are collinear. Find the value of x given AB = 3x, BC = 5x + 10. and AC = 74.​
Mars2501 [29]

Answer:

x = 8

Step-by-step explanation:

since it's a collinerar

or, AB+BC=AC

or, 3x+5x+10 = 74

or, 8x = 74-10

or, 8x = 64

or, x = 64/8

x = 8

6 0
3 years ago
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