The answer is that the first one is not the longer one the second one is.
the first one equals 2
the second one equals 5
If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
Answer:
We have: g(x)=(x+2)(x-1)(x-2)
multiply the 3 terms:
- (x+2)(x-1)(x-2)
- (x²-4)(x-1)
- x^3 -x²-4x+4
This is a polynimial function with 2 vertices
The roots are approximatively:
0.8 and -1.5
their images are:
1.9 and 8.8
plot these two vertices and draw some other points
here is a drawing:
X=-5, X=4 hope this helps
Answer:
what do you need help with
Step-by-step explanation: