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Lyrx [107]
3 years ago
11

3. What is 11% of $3,000? • A) $250 e B) $300 • C) $380 • D) $350​

Mathematics
2 answers:
Reptile [31]3 years ago
5 0

Answer:

$330.00

Step-by-step explanation:

IgorC [24]3 years ago
3 0

Hey there!

The word ‘of’ in math means multiply

And

11% of 3,000

= 11/100 * 3,000

= 11/100 * 3,000/1

= 11(3,000)/100(1)

= 33,000/100

= 33,000 ÷ 100/100 ÷ 100

= 330/1

= 330

Therefore, the answer is most likely: 330

(NONE of the ABOVE)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Kind of lost, can anyone please help me find the answer and explain? Id really appreciate it.
stich3 [128]

Answer:

B. 45

Step-by-step explanation:

do 12×12 which is 144 then Davide it by 2 because it's a triangle then do 9×3 which is 27 then subtract that from 72 and you get 45.

5 0
3 years ago
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Use the list below to find the upper quartile. 27, 5, 11, 13, 10, 8, 14, 18, 7
Alinara [238K]

Find the  median first. The middle of all the numbers.

5, 7, 8, 10, 11, 13, 14, 18, 27

11 is the median.

Then find the median of the upper quartile.

The upper quartile consists of numbers...

5, 7, 8, 10

Since it is an even set of numbers add the two in the middle and divided by two. So 7 plus 8=  15/2.

7.5 is your upper quartile.

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3 years ago
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Need help with math problems A-C. Please?
dolphi86 [110]
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4 years ago
You are trying to decide whether to use Uber or Lyft during a vacation. Uber charges $3 to pick up plus an additional $0.25 for
zubka84 [21]

Answer:

6 Miles and the cost is $4.50

Step-by-step explanation:

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7 0
3 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The​ plate, including the bound
rjkz [21]

Answer:

We have the coldest value of temperature T(\frac{3}{4},0) = -9/16. and the hottest value is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x

Let's take the partials derivatives.

T_{x}(x,y)=2x-\frac{3}{2}=0

T_{y}(x,y)=4y=0

So, we can find the critical point (x,y) of T(x,y).

2x-\frac{3}{2}=0

x=\frac{3}{4}

4y=0

y=0

The critical point is (3/4,0) so the temperature at this point is: T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})

T(\frac{3}{4},0)=-\frac{9}{16}    

Now, we need to evaluate the boundary condition.

x^{2}+y^{2}=1

We can solve this equation for y and evaluate this value in the temperature.

y=\pm \sqrt{1-x^{2}}

T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x  

T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2

Now, let's find the critical point again, as we did above.

T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0            

x=-\frac{3}{4}    

Evaluating T(x,y) at this point, we have:

T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2  

T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}

Now, we can see that at point (3/4,0) we have the coldest value of temperature T(\frac{3}{4},0) = -9/16. On the other hand, at the point -(3/4),\frac{\sqrt{7}}{4}) we have the hottest value of temperature, it is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

I hope it helps you!

4 0
3 years ago
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