5-3+10+137 10 and 137 are your numbers hope this helped
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Answer:
i think its a
Step-by-step explanation:
Answer:
-15 and 1
Step-by-step explanation:
-15x1=-15
-15+1= -14
204, because each day 6 goes up, so 34 x 6 = 204. Hope this helps :)