3 years ago

Find the product 8×25×23=

Mathematics

1 answer:

Ivenika [448]3 years ago

5 0

4600 is the answer to that ok mutiply 8×25×23

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if one point is located at (-5,3) and another point is located at (7,-4). find the distance between the points. round to the nea

Novay_Z [31]

Answer:

13.9

Step-by-step explanation:

Use the distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\\\\d = \sqrt{(7 - (-5))^2 + (-4-3)^2}\\d = \sqrt{(12)^2 + (-7)^2}\\d = \sqrt{144 + 49}\\d = \sqrt{193}\\$

The square root of 193 rounded to the nearest tenth is 13.9.

7 0

2 years ago

Find the product of (2x-3) and (x+3)

miss Akunina [59]

Answer:

(2x - 3) * (x + 3)

=> (2x * x) + (-3 * 3)

=> 2x - 9

=> 2x -9

If my answer helped, kindly mark me as the brainliest!!

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3 0

2 years ago

#1 2x-16<-18

Evgesh-ka [11]

Answer:

if it's finding x

#1 x<-1

#2 x<4

Step-by-step explanation:

2x-16<-18

add 16 to both sides

2x<-2

then divide 2 to both sides

x<-1

2x-16+4x<8

add like terms

6x-16+<8

add sixteen to both sides

6x<24

divide six to both sides

x<4

5 0

3 years ago

Help!

inessss [21]

Answer:

2 inches is the height of the box.

Step-by-step explanation:

4 0

2 years ago

The value of a house decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer) in

Westkost [7]

Answer: The total percentage loss would be 67%.

Step-by-step explanation:

Since we have given that

Rate of decline each year = 20%

Number of years = 5

We need to find the total percentage loss in value of the house at the end of 5 years.

So, Total percentage loss would be

$1-(1-\dfrac{r}{100})^5\\\\=1-(1-\dfrac{20}{100})^5\\\\=1-(\dfrac{4}{5})^5\\\\=1-(0.8)^5\\\\=0.67\\\\\approx 67%$

Hence, the total percentage loss would be 67%.

8 0

2 years ago