12 x 9 = 108
2 x 9 = 18
108 + 18 = 126
answer
<span>126 in² (3rd choice)</span>
Answer:
Case 1 - 50388 ways when the couple is there in the group of 8 people selected out of 20 employees.
Case 2 - 75582 ways when the couple is not there in the group of 8 people selected out of 20 employees.
Step-by-step explanation:
Given
The couple within the group can not be separated and hence instead of taking total 20 employees , it must be taken as 19 employees.
Now if the couple is there in the selected group of 8 people, then total 7 needs to be selected out of 19 and hence the total number of ways of selecting 7 people out of 19 is
= 50388
If the couple is not there in the selected group of 8 people, then the total number of ways of selecting 8 people out of 19 is
= 75582
The difference would be 7
Answer: probability = 0.0
Step-by-step explanation:
Out of 12 cars, 8 have MA licence plates (4 do not have)
Then we have 4 cars with out of state plates.
Then, out of these 12 cars we can not not have more than 4 cars with out of state plates (because there are only 4) then he never can se 9 cars with out of state plates.
The probability of seing 9 cars with out of state plates is 0.