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worty [1.4K]
3 years ago
6

Help with this answer fast!!!

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0
I think the answer is b
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Please helpp mee huhu
horsena [70]

Answer:

Can u show the whole question

8 0
2 years ago
N is a positive integer.Explain why n(n-1) must be an even number.
V125BC [204]

Answer:

n and (n - 1) are consecutive integers.

Step-by-step explanation:

We are given 'n', a positive integer.

This 'n' can either be odd or even.

Case I:

When 'n' is odd

The n - 1 is even.

Note that the product of odd and even is always even. That is the product of n and (n - 1) is even.

Case II:

when 'n' is even

Then n - 1 is odd.

Again, using the similar logic we can say that the product of n and n - 1 should be even because here, 'n - 1' is even and 'n' is odd.

4 0
3 years ago
For his yearly vacation, Colton plans to spend $350 on train tickets, $200 on food, $150 on accommodations, and $50 on miscellan
scoundrel [369]

Answer: He would spend 750$ on the entire vacation.

Step-by-step explanation: Simple addition, 350+150 (Always do the two odd ones first) which equals 500, 500+200 equals 700, and 700+50 equals  750, which gives your answer of 750$'s for the whole vacation.

5 0
3 years ago
Read 2 more answers
What is the slope of y = 5x?
9966 [12]

Answer:

The slope of the line is -5

4 0
3 years ago
Read 2 more answers
Suppose that you draw two cards from a deck. After drawing the first card, you do not put the first card back in the deck. What
AVprozaik [17]

Answer:

The correct answer is 0.05882.

Step-by-step explanation:

A deck of cards have 52 cards, 13 cards of each suit.

We are drawing two cards without replacement.

We need to find the probability of getting a diamond as the first card.

Favorable outcomes are 13 and total number of outcomes are 52.

Thus this probability is \frac{13}{52} = \frac{1}{4}.

Now for the next draw we again want to pick a diamond card.

Favorable outcomes are 12 and total number of leftover cards are 51.

Thus this probability is \frac{12}{51}.

Now the probability that both cards are diamonds is \frac{1}{4} × \frac{12}{51} = \frac{3}{51} = \frac{1}{17} = 0.0588235 ≈ 0.05882

4 0
3 years ago
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