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Tcecarenko [31]
3 years ago
11

a firm wants to select a group of 8 out of its 20 employees to attend a Business trip .in how many ways can this be done if ther

e is a couple who must not be separated​
Mathematics
1 answer:
inna [77]3 years ago
3 0

Answer:

Case 1 - 50388 ways when the couple is there in the group of 8 people selected out of 20 employees.

Case 2 - 75582 ways when the couple is not there in the group of 8 people selected out of 20 employees.

Step-by-step explanation:

Given

The couple within the group can not be separated and hence instead of taking total 20 employees , it must be taken as 19 employees.

Now if the couple is there in the selected group of 8 people, then total 7 needs to be selected out of 19 and hence the total number of ways of selecting 7 people out of 19 is

^7C_{19} = 50388

If the couple is not there in the selected group of 8 people, then the total number of ways of selecting 8 people out of 19 is

^8C_{19} = 75582

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A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
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Answer:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

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And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

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