Answer:
1) -184
2) 13
-3(
)+4
Step-by-step explanation:
For problem number 1, Let's start by substituting all the x's for -3
So the equation will look like
p(-3)=
-
+7(-3)-10
Now, lets simplify by solving the exponents
First we'll do 
which equals -27
Now we'll do 
which equals 9
So now our equation looks like
p(-3)=4(-27)-5(9)+7(-3)-10
Now, we are going to multiply all these numbers
First 4(-27) which equals -108
Now -5(9) which equals -45
And finally 7(-3) which equals -21
Now our equation looks like
p(-3)= -108-45-21-10
Now we can solve
-108-45-21-10=-184
Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answer:
Step-by-step explanation:
According to the diagram ,
Hypotenuse = 10√3
Opposite = x
Adjacent = y
α = 60
Using SOHCAHTOA ,
Sin α = opp / hyp
Sin 60= x/10√3
√3/2= x/10√3
x = 15
Pythagoras theorem ;
Hypotenuse ^2 = Opposite ^2 +Adjacent ^2
10√3 ^2 = 15^2+ y^2
300 = 225 +y ^2
300 -225 = y^2
75 = y^2
y = √75y
y = 5√3
x = 1/120
i did not see the comment about the 1/5 until now
hope this helps
