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3 years ago

Write the equation of the line perpendicular to y=1/5x-11 passing through the point (0,-8)

Mathematics

1 answer:

Lilit [14]3 years ago

5 0

Step-by-step explanation:

the slope of a line function is always the factor of x.

in our case here : 1/5

it is the ratio y/x indicating how many units y changes, when x changes a certain amount of units.

in our case that means y increases by 1 for every increase of x by 5.

now, the perpendicular slope simply changes x and y upside-down and flips the sign.

so, here the perpendicular slope is : -5/1 = -5

the line function looks therefore like

y = -5x + b

b is the y-intercept, and we get it by using the coordinates of the point for x and y :

-8 = -5×0 + b = b

so, the full line function is

y = -5x - 8

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Ayuda cual es el valor numerico de -11ab?

Dmitrij [34]

Can u translate this to English so we can respond and answer please?

8 0

2 years ago

16. Find the value of y.

devlian [24]

y + (2x -12) = 180 (since they are supplementary angles)

(2x-12) = 96 ( since they are alternate exterior angle)

2x = 96 + 12

2x = 108

x = 108/2

x = 54.

y+( 2x-12)=180

y+(2× 54 -12) = 180

y + (108-12) = 180

y + 96 = 180

y= 180-96

y = 84.

8 0

2 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago

I need help plz help

Lana71 [14]

2. 89
3. 568
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all u do is add

8 0

3 years ago

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189.271 in expanded form

Nookie1986 [14]

Answer:

189.271 in expanded form is (1 x 100) + (8 x 10) + (9 x 1) + (2/10) + (7/100) + (1/1000)

Step-by-step explanation: hope this helps <3

7 0

2 years ago

Read 2 more answers