Answer:
1.75 gallons
Step-by-step explanation:
First, we need to calculate how far the hike is going up the trail. They first hike 2 miles and then another 1.75 miles after resting so...
2 + 1.75 = 3.75 miles
The trail is 3.75 miles long, the question states that the return path is 0.5 miles shorter, therefore...
3.75 - 0.5 = 3.25 miles
Leaving us with a total hiking distance of
3.75 + 3.25 = 7 miles.
Since each hiker will carry 0.25 gallons for each mile we simply need to multiply this amount by the total number of miles in the hike.
7 * 0.25 = 1.75 gallons
Finally, we can see that each hiker will carry a total of 1.75 gallons of water for the entire hike.
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections
Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = 
Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.
Note that there are 24 hours in 1 day, and 60 minutes in 1 hour
First, multiply 25 with 24
25 x 24 = 600
Next, add 600 with 9 hours
600 + 9 = 690
Note that there are 60 minutes in 1 hour. Divide 7 minutes with 60
7/60 = ~0.12 (rounded)
~690.12 hours is your answer
hope this helps
Answer:
Step-by-step explanation:
Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.
We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.
I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.
The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.
