Answer:
yes
Step-by-step explanation:
the FIRST derivative of a function tells us the slope of a tangent line to the curve at any point. if is positive, then the curve must be increasing. If is negative, then the curve must be decreasing.
the SECOND derivative gives us the slope of the slope function (in other words how fast the slope of the original function changes, and if it is accelerating up - positive - or if it is avengers down - negative).
so, the first derivative would be fully sufficient to get the answer of if the slope of the function at that point is positive or negative.
but because it is only a "if" condition and not a "if and only if" condition, the statement is still true.
there are enough cases, where the slope is positive, but the second derivative is not > 0 (usually = 0).
but if even the second derivative is positive, then, yes, the slope of the original function must be positive too.
If a shape is translated (has it's vertex' coordinates moved/changed), then it retains its original values but just has different vertex coordinates.
Thus since DE is equal to UV, then,
DE = UV; substitution:
5=5
Remember this, DOOP
This stands for decimal, two zeros, then percent.
So, what you do is, since 1.513 is a decimal, you move the decimal two places to the right. You get 151.3
Therefore, 1.513 is 151.3%
Let x=small circle
2x = bigger circle
πx^2 + π(2x)^2 = 80π
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 16
x = +/- 4
but we need the positive one because there's no negative measurement so
the answers are:
4m and 8m
The answer should be A simple interest
