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Sonja [21]
10 months ago
11

Graph and label the image of the figure below after a dilation by a factor of 1/2.

Mathematics
1 answer:
neonofarm [45]10 months ago
3 0
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

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olchik [2.2K]

Answer:  Ratio of Parts

<u>Step-by-step explanation:</u>

\text{Ratio of sides:}\ \dfrac{ST}{WS+ST}=\dfrac{66}{6+66}=\dfrac{66}{72}=\dfrac{11}{12}\\\\\\\text{Ratio of bases:}\ \dfrac{TU}{TU+UV}=\dfrac{44}{44+4}=\dfrac{44}{48}=\dfrac{11}{12}\\\\

The ratios are equal so the triangles are similar.

7 0
3 years ago
Which points are solutions to the system of inequalities shown below? Check all that apply.
Alexandra [31]
I: y<2*x
II: y<8
III: x>2

a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution

b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution

c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution

d: (1,-4):
I: -4<2*1
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II: -4<8 ?yes
III: 1>2 ?no
This is not a solution

e: (4,-2):
I: -2<2*4
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II: -2<8 ?yes
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f: (5,9):
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so a,b,c,e are solutions and d,f not
6 0
3 years ago
To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
2 years ago
Its
damaskus [11]

Answer:

P(Green\ and\ Green) = \frac{25}{144}

Step-by-step explanation:

Given

Green=5

Blue = 7

Required

P(Green\ and\ Green)

This is calculated as:

P(Green\ and\ Green) = P(Green) * P(Green)

Since, it is a probability with replacement, we have:

P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}

So, we have:

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5 0
3 years ago
Image of question provided
inna [77]

Answer:

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f(t)=at^{2}+bt

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12=a+b

0=16a+4b

We need to divide the second equation by -4 and sum both equations

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12=-3a\\a=\frac{12}{-3}\\ a=-4

Then, we use this value to find the other variable

12=a+b\\12=-4+b\\b=12+4\\b=16

<h3>Therefore, the quadratic function that models the situation is</h3>

f(t)=-4t^{2} +16t  or  f(t)=-4t(t-4)

According to this expression, after 2 seconds, the height is 16 feet.

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7 0
3 years ago
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